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snow_lady [41]
3 years ago
13

what is the surface area of this square pyramid with a base length of 4 centimeters and slant height of 9 centimeters? HELP PLEA

SE!!!!

Mathematics
1 answer:
Natalija [7]3 years ago
6 0

Answer:

The surface area of a square pyramid = 1/2 * slant height * base perimeter + area of base

The slant height is 8 cm

The base perimeter is 4 * 5 cm = 20 cm

The area of the base is 5 cm * 5 cm = 25 cm**2

Plugging into the formula the area =

1/2 * 8 cm * 20 cm + 25 cm**2 =

4 cm * 20 cm + 25 cm**2 =

80 cm**2 + 25 cm**2 = 105 cm**2

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madreJ [45]
For this problem you are going to need to know the point-slope equation which is: 
y-y₁=m(x-x₁)

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Since all they are asking for is for you to put it into a formula this will be your answer.
8 0
3 years ago
The altitude of a triangle is increasing at a rate of 1 cm/ min while the area of the triangle is increasing at a rate of 2 cm2
serg [7]
Ya, calculus and related rates, such fun!




everything is changing with respect to t

altitude rate will be dh/dt and that is 1cm/min
dh/dt=1cm/min

area will be da/dt which is increasing at 2cm²/min
da/dt=2cm²/min

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alright

area=1/2bh
take dervitivie of both sides
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solve for db/dt
distribute
da/dt=1/2(db/dt)(h)+1/2(dh/dt)(b)
move
da/dt-1/2(dh/dt)(b)=1/2(db/dt)(h)
times 2 both sides
2da/dt-(dh/dt)(b)=(db/dt)(h)
divide by h
(2da/dt-(dh/dt)(b))/h=db/dt

ok
we know
height=10
area=100
so
a=1/2bh
100=1/2b10
100=5b
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so
h=10
b=20
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therefor
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(-16cm²/min)/10cm=db/dt
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the base is decreasing at 1.6cm/min
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Answer:

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