Ask question

Ask question

All categories

pishuonlain [190]

3 years ago

12

Graph the system of equations. Then determine whether the system has no solution, one solution, or infinitely many solutions. If

the system has one solution, name it.
y = $\frac{3}{2}$ x
y = -x + 5

WILL PICK BRAINLIEST ANSWER, THANK YOU, AND 5 STAR FOR FULL EXPLANATION. :)

1 answer:

andrew11 [14]3 years ago

5 0

Answer:

1 1/2

Step-by-step explanation:

You might be interested in

How do you find the mean, median and range

astra-53 [7]

for mean you add every number and divide it by the amount of numbers in the data set

for median you put the numbers in order and find the middle number, if there is no middle get the mean for the two middle numbers

range is basically the lowest and highest number

5 0

2 years ago

Read 2 more answers

Help Please!!!!!!!!!!!<br><br> Questions 9 and 10

Sphinxa [80]

Answer:

Step-by-step explanation:

9

1. ∠ACB ≅∠ECD ; vertical angles are congruent (A)

2. C is midpoint of AE ; given

3. AC ≅CE; midpoint divides the line segment in 2 congruent segments (S)

4.AB║DE; given

5. ∠A≅∠E; alternate interior angles are congruent (A)

6. ΔABC≅ΔEDC; Angle-Side-Angle congruency theorem

10

1. YX≅ZX; given (S)

2. WX bisects ∠YXZ; given

3. ∠YXW≅∠ZXW; definition of angle bisectors (A)

4. WX ≅WX; reflexive propriety(S)

5. ΔWYX≅ΔWZX; Side-Angle-Side theorem

3 0

2 years ago

At the grocery, peaches cost $2.60 per pound. Grace bought 2.3 pounds of peaches.

brilliants [131]

The total cost would be $5.98
hope this helps! :)

3 0

2 years ago

Suppose we have an unfair coin that its head is twice as likely to occur as its tail. a)If the coin is flipped 3 times, what is

Alenkinab [10]

Answer: a) 0.2222, b) 0.3292, c) 0.1111

Step-by-step explanation:

Since we have given that

Let the probability of getting head be p.

Since, its head is twice as likely to occur as its tail.

$p+\dfrac{p}{2}=1\\\\\dfrac{3p}{2}=1\\\\p=\dfrac{2}{3}$

a)If the coin is flipped 3 times, what is the probability of getting exactly 1 head?

So, here, n = 3

$p=\dfrac{2}{3}$

$q=\dfrac{1}{3}$

Now,

$P(X=1)=^3C_1(\dfrac{2}{3})^1(\dfrac{1}{3})^2=0.2222$

b)If the coin is flipped 5 times, what is the probability of getting exactly 2 tails?

2 tails means 3 heads.

So, it becomes,

$P(X=3)=^5C_3(\dfrac{2}{3})^3(\dfrac{1}{3})^2=0.3292$

c)If the coin is flipped 4 times, what is the probability of getting at least 3 tails?

$P(X\leq 1)=\sum _{x=0}^1^4C_x(\dfrac{2}{3}^x(\dfrac{1}{3})^{4-x}=0.1111$

Hence, a) 0.2222, b) 0.3292, c) 0.1111

8 0

2 years ago

Y= 4x - 3<br> How do I graph this equation?

nevsk [136]

Answer:

y intercept is -3, go up 4 over 1

Step-by-step explanation:

7 0

3 years ago