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sergeinik [125]
3 years ago
15

Which is the equation of a line that has a slope of One-half and passes through point (2, –3)?y = one-half x minus 4 y = one-hal

f x minus 2 y = one-half x + 2 y = one-half x + 3y = one-half x minus 4
y = one-half x minus 2
y = one-half x + 2
y = one-half x + 3
Mathematics
2 answers:
swat323 years ago
8 0

Answer: y = one-half x + 2

Step-by-step explanation:

So the options are in y=mx+b aka slope intercept form, so since the slope is 1/2, and passes through (2,-3) the equation will be y=1/2x+2. So the answer is y = one-half x + 2. Some things to remember is that b=y-intercept, and m=slope.

----------------------

Hope this helps, have a BLESSED and wonderful day! :-)

-Cutiepatutie

lubasha [3.4K]3 years ago
6 0

Answer:

The answer is y=1/2x plus 2

Step-by-step explanation:

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Which evidence from the text best supports the idea that women astronauts are not unusual anymore?
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Answer:

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Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
For the system of equations that follows, use Gaussian elimination to obtain an equivalent system whose coefficient matrix is in
Rainbow [258]

Answer:

\begin{Vmatrix}1 & 0 & 0& 46/41 &180/41\\0 & 1 & 0&1/41 &-5/41\\0&0 & 1 & -8/41& -42/41\end{Vmatrix}

Step-by-step explanation:

From the question we are told that

System of equations given as

x₁ + 3x₂ + x₃ + x₄ = 3;

2x₁ - 2x₂ + x₃ + 2x₄ = 8;

x₁ - 5x₂ + x₄ = 5

Matrix form

\begin{Vmatrix}1 & 3 & 1&1&3\\2 & -2 & 1&2&8\\0&1 & -5 & 1& 5\end{Vmatrix}  \begin{Vmatrix}x_1\\x_2\\x_3\\x_4\end{Vmatrix}

Generally the echelon reduction is mathematically applied as

\begin{Vmatrix}1 & 3 & 1&1&3\\2 & -2 & 1&2&8\\0&1 & -5 & 1& 5\end{Vmatrix}

Add -2 times the 1st row to the 2nd row

\begin{Vmatrix}1 & 3 & 1&1&3\\0 & -8 & -1&0&2\\0&1 & -5 & 1& 5\end{Vmatrix}

Multiply the 2nd row by -1/8  

\begin{Vmatrix}1 & 3 & 1&1&3\\0 & 1 & 1/8&0&-1/4\\0&1 & -5 & 1& 5\end{Vmatrix}

Add -1 times the 2nd row to the 3rd row

\begin{Vmatrix}1 & 3 & 1&1&3\\0 & 1 & 1/8&0&-1/4\\0&0 & -41/8 & 1& 21/4\end{Vmatrix}

Multiply the 3rd row by -8/41

\begin{Vmatrix}1 & 3 & 1&1&3\\0 & 1 & 1/8&0&-1/4\\0&0 & 1 & -8/41& -42/41\end{Vmatrix}

Add -1/8 times the 3rd row to the 2nd row

Add -1 times the 3rd row to the 1st row

\begin{Vmatrix}1 & 3 & 0&49/41&165/41\\0 & 1 & 0&1/41 &-5/41\\0&0 & 1 & -8/41& -42/41\end{Vmatrix}

Add -3 times the 2nd row to the 1st row

\begin{Vmatrix}1 & 0 & 0& 46/41 &180/41\\0 & 1 & 0&1/41 &-5/41\\0&0 & 1 & -8/41& -42/41\end{Vmatrix}

3 0
2 years ago
Mrs. Norris is paid 5% commission on each boat he sells. What is his commission on a boat that he sells for $125,000
miv72 [106K]
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8 0
3 years ago
Don’t understand need help please
Airida [17]

Answer:

Step-by-step explanation:

∠A = arctan(33/43) ≈ 37.5°

AB = √(43² + 33²) = √2938

Law of Sines

∠C = arcsin(sinA ⋅ AB/BC) ≈ 34.7°

5 0
2 years ago
Someone please help me with this one quick
astraxan [27]

The length of AC is 16 km.

Solution:

Given data:

AB = c = 14 km, ∠A = 30° and ∠B = 89°

AC = b = ?

<u>Let us first find angle C:</u>

<em>Sum of all angles in a triangle = 180°</em>

m∠A+ m∠B + m∠C = 180°

30° + 89° + m∠C = 180°

119° + m∠C = 180°

Subtract 119° from both sides, we get

m∠C = 61°

<u>To find the length of AC:</u>

<em>Using sine formula:</em>

$\frac{b}{\sin B } =\frac{c}{\sin C}

Substitute the given values in the formula.

$\frac{b}{\sin 89^\circ } =\frac{14}{\sin 61^\circ }

Multiply by sin 89° on both sides.

$\sin 89^\circ \times \frac{b}{\sin 89^\circ } =\frac{14}{\sin 61^\circ } \times \sin 89^\circ

$b=\frac{14}{0.8746 } \times0.9998

b=16

The length of AC is 16 km.

4 0
2 years ago
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