In math for we have:
2x-2=x+64
which turns into:
x=66
(subtract x from right) & (add two from left)
Answer:
1) 7m
2) 13
3) 4x^2y
4) 6s^3t^4
Step-by-step explanation:
gcf means the the greatest factor that works for both terms
1) 21m^3 and 28m
let's first find the gcf for the coefficient
21 and 28, the gcf is 7. (hopefully thats easy to explain)
the gcf for the variables is the same mindset as the numbers
m^3 and m, both can be factored by m
so the gcf is 7 * m which is 7m
2)
13x and 26
let's first find the gcf for the coefficient
13 and 26, gcf is 13
there's only one variable, x, so there's not gcf for that
so the gcf is just 13
3)
8x^2y and -12x^3y^2
let's first find the gcf for the coefficient
8 and -12, the gcf is 4 (you can also say -4)
for the variables , same mindset
x^2y and x^3y^2
the gcf for x is x^2, and for y it is just y
so 4 * x^2 * y = 4x^2y
by understanding 3) hopefully you can understand 4)
pls comment for any questions
Estimated amount that Mr. Jones thought would be spending each week for grocery = $120
Amount actually spent by Mr.Jones in the grocery store = $94
Error in calculation of the amount of spending = (120 - 94) dollars
= $26
Percentage error in calculation = (26/120) * 100
= (13/6) * 10
= 130/6
= 21.666 percent
= 21.67 percent
So there is 21.67% error in the calculation of Mr. Jones. I hope you got the answer you were looking for.
The height of the ball at ground level would be 0 feet.
Set h to 0 and solve for t:
Rewrite the equation as
-5t^2 -2t +49 = 0
Factor -1 out of the equation to get:
5t^2 + 2t -49 = 0
Use the quadratic formula:
-b +/- sqrt(b^2 -4(ac) / 2a
Where a = 5, b = 2 and c = -49
The quadratic formula becomes:
-2 +/-sqrt(2^2 – 4(5*-49) / (2*5)
Simplify to get :
T = -2 +/-sqrt246 / 10
T = 2.936 and – 3.336
Since the time has to be a positive value t = 2.936 seconds.
Rounded to the nearest hundredth = 2.94 seconds.
