1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ann [662]
3 years ago
13

If f(x)=2x^2+2 and g(×)=x^2-1 find (f-g)(x)

Mathematics
1 answer:
Elza [17]3 years ago
8 0
f(x)=2x^2+2\qquad\qquad g(x)=x^2-1\\\\\\
\big(f-g\big)(x)=f(x)-g(x)=(2x^2+2)-(x^2-1)=2x^2+2-x^2+1=\\\\=\boxed{x^2+3}

Answer B)
You might be interested in
The cost in dollars to print n books is 500 + 10n. How many books are printed for a cost of $15 000?
12345 [234]
N= the # of books
So you're trying to find n and you have the cost for the printed books, which is 15,000, so you would set up your equation like this:
15,000=500+10n 
Subtract 500 from each side
14850=10n 
Divide by 10
n=1,485 books are printed
8 0
3 years ago
How many ways are there to choose eight coins from a piggy bank containing 100 identical pennies and 80 identical nickels?
Ahat [919]
I think it's two but I'm not sure don't count on it.
3 0
3 years ago
A painter can paint a building in 15 days and a coworker can do the same job in 10 days. If the first painter starts and 3 days
Sonja [21]

Answer:  7.8 days

<u>Step-by-step explanation:</u>

Painter can get the job done in 15 days so gets \dfrac{1}{15} of the job done in 1 day.

Coworker can get the job done in 10 days so gets \dfrac{1}{10} of the job done in 1 day.

Together, they get \dfrac{1}{15}+\dfrac{1}{10} of the job done in 1 day.

Painter worked for 3 days so completed \dfrac{1}{15}(3)=\dfrac{1}{5} of the job.

That leaves a remaining of 1-\dfrac{1}{5}=\dfrac{4}{5} of the job to be completed.

Let x represent the number of days it will take them to work together.

Painter + Coworker = Together

\dfrac{1}{15}(x)\quad +\quad \dfrac{1}{10}(x)\quad =\quad \dfrac{4}{5}

Multiply by 30 to eliminate the denominator:

\dfrac{1}{15}(x)(30) +\ \dfrac{1}{10}(x)(30) = \dfrac{4}{5}(30)

Simplify and solve for x:

    2x + 3x = 24

            5x = 24

              x=\dfrac{24}{5}

              x = 4.8

Remember that Painter worked 3 days alone in addition to the 4.8 days they worked together.

So the total time to paint the building is 3 + 4.8 = 7.8

7 0
3 years ago
Which of the following is equal to [(x^2 y^3)^-2/x^6 y^3 z)^2]^-3
maksim [4K]

Answer:

it's A,B and D , Edge 2021

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Unit l2 trigonometry homework 6 law of cosines <br>Does anyone know the answer please help!​
guapka [62]

Step-by-step explanation:

The law of cosine states that:

C^2=B^2+A^2-2AB\cos(\theta), where C is the side opposite of angle theta, and A and B are the adjacent sides of the angle.

In this case, A is equal to 21, and B is equal to 30 (or it could also be the other way around). That means that:

C^2=21^2+30^2-2\cdot21\cdot30\cos(73)\\C=\sqrt{21^2+30^2-2\cdot21\cdot30\cos(73)}=\boxed{31.186722} (to nearest 6 digits)

7 0
3 years ago
Read 2 more answers
Other questions:
  • The function f(x) = 2x is transformed to g(x) = 2x – 3. What type of transformation has occurred?
    12·1 answer
  • Im stuck on this question, plz help
    6·1 answer
  • Evaluate 1/2t + 3/8 when t = 1/4
    6·1 answer
  • Round all answers to decimal places if necessary 3batteries for $4.80
    9·2 answers
  • Simplify anyone........
    14·1 answer
  • I WILL MARK THE BRAINLIEST!!! One math question. please explain as well
    6·1 answer
  • Select the least common multiple of 12 and 15. A. 3 B. 15 C. 60 D. 180
    9·1 answer
  • Chang's art class is 9 hours long. how long is his class in minutes?
    14·2 answers
  • Karim's dog weighs 1.5 pounds less than double the weight of Frank's dog. Karim's dog weighs 15 pounds. Which equation and solut
    10·1 answer
  • Evaluate. Write your answer as a fraction or mixed number in simplest form.
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!