Question 6 smart ppl i need you !!!!!!!!!!!!!!

E=VIT how would I isolate the “V” variable

Zigmanuir [339]

Answer:

$V =\frac{E}{IT}$

Step-by-step explanation:

You can isolate the "V" variable by dividing by IT on both sides:

$\frac{E}{IT} =\frac{VIT}{IT}$

On the left, the IT from the top and bottom cancel, leaving you with just V:

$V =\frac{E}{IT}$

6 0

2 years ago

Which expression is equivalent to (3a5 + b4)2

makvit [3.9K]

Is it multiple choice or do you have to write a answer?

8 0

3 years ago

Read 2 more answers

If AC is parallel to DE, find X

UNO [17]

Answer: x = 50

Concept:

Here, we need to know the idea of alternative interior angles and the angle sum theorem.

Alternative interior angles are angles that are formed inside the two parallel lines, and the values are equal.

The angle sum theorem implies that the sum of interior angles of a triangle is 180°

If you are still confused, please refer to the attachment below or let me know.

Step-by-step explanation:

Given information:

AC ║ DE

∠ABC = 85°

∠A = 135°

Find the value of ∠BAC

∠A + ∠BAC = 180° (Supplementary angle)

(135°) + ∠BAC = 180°

∠BAC = 45°

Find the value of ∠BCA

∠ABC + ∠BAC + ∠BCA = 180° (Angle sum theorem)

(85°) + (45°) + ∠BCA = 180°

∠BCA = 50°

Find the value of x (∠EBC)

∠EBC ≅ ∠BCA (Alternative interior angles)

Since, ∠BCA = 50°

Therefore, ∠EBC = 50°

$\Large\boxed{x=50}$

Hope this helps!! :)

Please let me know if you have any questions

8 0

1 year ago

A cash box contains $74 made up of quarters, half-dollars, and one-dollar

Strike441 [17]

Answer:

25 one-dollar coins, 16 half-dollar coins, and 164 quarters

Step-by-step explanation:

First, set up equations based on the information given:

$0.25q+0.50h+1.00d=74$

$\displaystyle{h=\frac{3}{5}d+1}$

$q=4(d+h)$

Then, substitute q in the first equation with the expression from the third equation:

$0.25[4(d+h)]+0.50h+1.00d=74\\1d+1h+0.50h+1.00d=74\\2d+1.5h=74$

Next, substitute h in that equation with the expression from the second equation:

$\displaystyle{2d+1.5(\frac{3}{5}d+1)=74}$

$2d+0.9d+1.5=74\\2.9d+1.5=74$

Solve for d, the number of one-dollar coins:

$2.9d+1.5=74\\2.9d=72.5\\d=25$

Substitute 25 for d in the second equation to find h, the number of half-dollar coins:

$\displaystyle{h=\frac{3}{5}d+1}$

$\displaystyle{h=\frac{3}{5}(25)+1}$

$h=15+1\\h=16$

Substitute 25 for d and 16 for h in the third equation to find q, the number of quarters:

$q=4(d+h)\\q=4(25+16)\\q=4(41)\\q=164$

Then, verify that the coins total $74:

$0.25(164)+0.50(16)+1.00(25)=74\\41+8+25=74\\74=74\\\text{Check.}$

Next, verify that the number of half-dollar coins is one more than three-fifths of the number of one-dollar coins:

$\displaystyle{h=\frac{3}{5}d+1}$

$\displaystyle{16=\frac{3}{5}(25)+1}$

$16 = 15 + 1\\16 = 16\\\text{Check.}$

Finally, verify that the number of quarters is four times the number one-dollar and half-dollar coins together:

$q=4(d+h)\\164=4(25+16)\\164=4(41)\\164=164\\\text{Check.}$

6 0

3 years ago

2 Nine identical circles are cut from a square sheet of paper whose sides are

Ivanshal [37]

Answer:

278.64cm²

Step-by-step explanation:

Area of the sheet left out = Area of the square - Area of the 9 circles

Area of the square = L^2

L is the side length of the square

A = 36^2

Area of the square = 1296cm^2

Diameter of a circle = 38/3 = 12cm

Area of a circle = πr²

r is the radius = 12/2 = 6cm

Area of a circle = 3.14(6)²

Area of a circle = 3.14 * 36

Area of a circle = 113.04cm²

Area of 9 circles = 9 * 113.04

Area of 9 circles = 1,017.36cm²

Area of the left over = 1296 - 1,017.36

Area of the left over = 278.64cm²

6 0

2 years ago