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Reika [66]
3 years ago
12

An organization is conducting a study to see if hazardous waste sites pose health risks for cancer or other conditions, such as

birth defects or nerve or liver damage.
Which of the following specialized information systems would give the organization the information it is looking for?

Superfund information systems
Geographic information systems
Emergency department information systems
Electronic medical record systems
Computers and Technology
1 answer:
denpristay [2]3 years ago
8 0

Answer:

Emergency department information systems

Explanation:

I think this is the answer

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1. Print out the string length of s1 2. Loop through characters in s2 with charAt() and display reversed string 3. Compare s2, s
konstantin123 [22]

Answer:

See explaination

Explanation:

public class StringLab9 {

public static void main(String args[]) {

char charArray[] = { 'C', 'O', 'S', 'C', ' ', '3', '3', '1', '7', ' ', 'O', 'O', ' ', 'C', 'l', 'a', 's', 's' };

String s1 = new String("Objected oriented programming language!");

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String s3 = new String(charArray);

// To do 1: print out the string length of s1

System.out.println(s1.length());

// To do 2: loop through characters in s2 with charAt and display reversed

// string

for (int i = s2.length() - 1; i >= 0; --i)

System.out.print(s2.charAt(i));

System.out.println();

// To do 3: compare s2, s3 with compareTo(), print out which string (s2 or s3)

// is

// greater than which string (s2 or s3), or equal, print the result out

if (s2.compareTo(s3) == 0)

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else if (s2.compareTo(s3) > 0)

System.out.println("s2 is greater");

else

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// To do 4: Use the regionMatches to compare s2 and s3 with case sensitivity of

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if (s2.substring(0, 8).compareTo(s3.substring(0, 8)) == 0)

System.out.println("They matched");

else

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// To do 5: Find the location of the first character 'g' in s1, print it out

int i;

for (i = 0; i < s2.length(); ++i)

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int index = 0, ans = 0;

String test = s2;

while (index != -1) {

ans = ans + index;

index = test.indexOf("class");

test = test.substring(index + 1, test.length());

}

System.out.println("Last location of class in s2 is: " + (ans + 1));

// To do 7: Extract a substring from index 4 up to, but not including 8 from

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System.out.println(s3.substring(4, 8));

} // end main

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7 0
3 years ago
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I hope this helps! Please make sure ask me if you need more clarity!
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Answer:

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Explanation:

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I guess the correct answer is application

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