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zhannawk [14.2K]
3 years ago
5

Find each missing angle Please

Mathematics
1 answer:
-BARSIC- [3]3 years ago
7 0

Answer:

m<1=61

m<2=40

m<3=60

m<4=80

m<5=100

Step-by-step explanation:

180/3=60

180/9=20

20x2=40

20x4=80

20x3=60

59+60=119

180-119=61

180-80=100

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The sum is -3.3z - 11
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3 years ago
Write 2,930,365 in expanded notation
Snowcat [4.5K]

Step-by-step explanation: The place value chart can help us write a number in expanded notation. When we put 2,930,365 into the place value chart, we can recognize that our number is equal to 2 millions + 9 hundred thousands + 3 ten thousands + 0 thousands + 3 hundreds + 6 tens + 5 units.

The place value chart is attached in the image provided.

5 0
3 years ago
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a man spends 42% of his salary on food and 12% on transport. if the amount he spent on food is Rs 16800, how much was his transp
FinnZ [79.3K]

The man's transport cost is Rs 4800

Step-by-step explanation:

  • Step 1: Given that the amount the man spent on food = Rs 16800 which is 42% of his salary. Form an equation where his salary is x.

42% of x = 16800

42/100 × x = 16800

42x = 1,680,000

x = 1,680,000/42 = Rs 40,000

∴ Salary is Rs 40,000

  • Step 2: Calculate the man's transport cost.

12% of 40000 = 12/100 × 40000 = Rs 4800

8 0
3 years ago
Need help pleaseI was bad at math in school so lwant to learn
aleksklad [387]

The probability of an event is expressed as

Pr(\text{event) =}\frac{Total\text{ number of favourable/desired outcome}}{Tota\text{l number of possible outcome}}

Given:

\begin{gathered} \text{Red}\Rightarrow2 \\ \text{Green}\Rightarrow3 \\ \text{Blue}\Rightarrow2 \\ \Rightarrow Total\text{ number of balls = 2+3+2=7 balls} \end{gathered}

The probability of drwing two blue balls one after the other is expressed as

Pr(\text{blue)}\times Pr(blue)

For the first draw:

\begin{gathered} Pr(\text{blue) = }\frac{number\text{ of blue balls}}{total\text{ number of balls}} \\ =\frac{2}{7} \end{gathered}

For the second draw, we have only 1 blue ball left out of a total of 6 balls (since a blue ball with drawn earlier).

Thus,

\begin{gathered} Pr(\text{blue)}=\frac{number\text{ of blue balls left}}{total\text{ number of balls left}} \\ =\frac{1}{6} \end{gathered}

The probability of drawing two blue balls one after the other is evaluted as

\begin{gathered} \frac{1}{6}\times\frac{2}{7} \\ =\frac{1}{21} \end{gathered}

The probablity that none of the balls drawn is blue is evaluted as

\begin{gathered} 1-\frac{1}{21} \\ =\frac{20}{21} \end{gathered}

Hence, the probablity that none of the balls drawn is blue is evaluted as

\frac{20}{21}

8 0
1 year ago
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sveta [45]

\frac{11-x}{3x+2} =\frac{1}{2}

Cross multiply

2(11-x) = 1(3x+2)

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22-2x = 3x+2

Subtract 22 from both sides

-2x = 3x-20

Subtract 3x from both sides

-5x = -20

Divide both sides by -5

x=4

5 0
4 years ago
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