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3 years ago

Plants remove which greenhouse gas from the atmosphere?

2 answers:

5 0

Hello there.

Question: <span>Plants remove which greenhouse gas from the atmosphere?

Answer: It is C. Carbon Dioxide. As you know, plants take in carbon dioxide and let out oxygen.

Hope This Helps You!
Good Luck Studying ^-^</span>

Paladinen [302]3 years ago

5 0

Answer:Plants remove CO2 greenhouse gas from the atmosphere

Explanation:Using daylight, plants and microorganisms soak up CO2 and emit oxygen. Those plants are then consumed by animals, who then convert the plants to energy and exhale CO2. Or if the plants don't get consumed, they die and decay, putting some carbon within the soil and returning some carbon to the atmosphere. Hence, from the above option, only carbon dioxide is taken by the plants by removing oxygen, so the cprrect option is C.

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Which statement is not true of alkenes?

sladkih [1.3K]

Answer:

Explanation:

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4 years ago

Which statement best describes the formula equation ci2(g)+2kbr(aq)-2kci(aq)+ Br2(i)

BARSIC [14]

The statement that describes the chemical reaction is D chlorine gas reacts with potassium bromide to form potassium chloride in solution and liquid bromide. The symbol "Cl" represents chlorine. The symbols in the brackets show the physical state of the substance, (g) is gaseous, (s) is solid, (aq) is aqueous and (l) is liquid.

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4 years ago

Which of the following statements best describes why electrons

Lubov Fominskaja [6]

Answer: Electons and protons have similar charges, and are therefore attracted to one another... I think

Explanation:

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3 years ago

G determine the concentration of an hbr solution if a 45.00 ml aliquot of the solution yields 0.6485 g agbr when added to a solu

Sunny_sXe [5.5K]

The molecular weight of silver bromide (AgBr) is 187.77 g/mole. The presence of the ions in solution can be shown as- AgBr (insoluble) ⇄ $Ag^{+}$ + $Br^{-1}$ .

45.00 mL of the aliquot contains 0.6485 g of AgBr. Thus 1000 mL of the aliquot contains $\frac{0.6485}{45}$ ×1000 = 14.411 gm-mole. Thus the solubility product $K_{sp}$ of AgBr = [ $Ag^{+}$ ]× $Br^{-}$ .

Or, 5.0× $10^{-13}$ = $S^{2}$ (the given value of solubility product of AgBr is 5.0× $10^{-13}$ and the charge of the both ions are same).

Thus S = (5.00× $10^{-13}$ ) $^{1/2}$ = 7.071× $10^{-7}$ g/mL.

Thus the concentration of Br $^{-1}$ or HBr is 7.071× $10^{-7}$ g/mL.

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4 years ago

Why Don't Birds Get Electrocuted When They Land on Electric Wires?

zloy xaker [14]

Answer:

Birds are able to sit on electrical power lines because the electrical current essentially ignores the bird's presence and continues to travel through the wire instead of through the bird's body. A bird's body is not a good conductor of electricity.

hope i helped

6 0

3 years ago