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vladimir1956 [14]
3 years ago
5

Eriq, a chemist, is running tests with four unknown elements. He has found that they all bond the same way, so he knows that the

y are in the same group on the periodic table of elements. The table shows other properties that Eriq observed. A 4-column table with 4 rows titled properties of four unknown elements. The first column titled element number has entries 1, 2, 3, 4. The second column titled melting point has entries 266 K, 172 K, 387 K, 53 K. The third column titled boiling point has entries 332 K, 239 K, 457 K, 85 K. The fourth column titled phase at room temperature has entries liquid, gas, solid, gas. These four elements are most likely in group 15. 16. 17. 18.
Chemistry
2 answers:
Reil [10]3 years ago
4 0

Answer:

in group 17

Explanation:

just took the quiz

kicyunya [14]3 years ago
3 0

Answer:

its group 17.

Explanation:

i got 100% on the quiz

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What is the volume of as sample that has a mass of 40.0 g and a density of 4.30 g/mL?
kati45 [8]

Explanation:

density = mass/volume so volume = mass/density = 40/4.30

4 0
2 years ago
A substance is found to consist of 1.900g of silver, 0.250g of nitrogen, and 0.850g of oxygen. what is the percent by mass of ox
Galina-37 [17]
The  percentage  by mass  of  oxygen  in  the  compound

find  the total  mass=(  1.900+  0250 +0.850) =  3
the  percentage  mass  mass of  oxgyen/total  mass  x100

that  is  (0.850/3)  x100=28.33%
7 0
3 years ago
A beaker with 155 mL of an acetic acid buffer with a pH of 5.000 is sitting on a benchtop. The total molarity of acid and conjug
OverLord2011 [107]

Answer:

ΔpH = 0.296

Explanation:

The equilibrium of acetic acid (CH₃COOH) in water is:

CH₃COOH ⇄ CH₃COO⁻ + H⁺

Henderson-Hasselbalch formula to find pH in a buffer is:

pH = pKa + log₁₀ [CH₃COO⁻] / [CH₃COOH]

Replacing with known values:

5.000 = 4.740 + log₁₀ [CH₃COO⁻] / [CH₃COOH]

0.260 =  log₁₀ [CH₃COO⁻] / [CH₃COOH]

1.820 = [CH₃COO⁻] / [CH₃COOH] <em>(1)</em>

As total molarity of buffer is 0.100M:

[CH₃COO⁻] + [CH₃COOH] = 0.100M <em>(2)</em>

Replacing (2) in (1):

1.820 = 0.100M - [CH₃COOH] / [CH₃COOH]

1.820[CH₃COOH] = 0.100M - [CH₃COOH]

2.820[CH₃COOH] = 0.100M

[CH₃COOH] = 0.100M / 2.820

[CH₃COOH] = <em>0.035M</em>

Thus: [CH₃COO⁻] = 0.100M - 0.035M = <em>0.065M</em>

5.40 mL of a 0.490 M HCl are:

0.0054L × (0.490mol / L) = 2.646x10⁻³ moles HCl.

Moles of CH₃COO⁻ are: 0.155L × (0.065mol / L) = 0.0101 moles

HCl reacts with CH₃COO⁻ thus:

HCl + CH₃COO⁻ → CH₃COOH

After reaction, moles of CH₃COO⁻ are:

0.0101 moles - 2.646x10⁻³ moles = <em>7.429x10⁻³ moles of CH₃COO⁻</em>

<em />

Moles of CH₃COOH  before reaction are: 0.155L × (0.035mol / L) = 5.425x10⁻³ moles of CH₃COOH. As reaction produce 2.646x10⁻³ moles of CH₃COOH, final moles are:

5.425x10⁻³ moles +  2.646x10⁻³ moles = <em>8.071x10⁻³ moles of CH₃COOH</em>. Replacing these values in Henderson-Hasselbalch formula:

pH = 4.740 + log₁₀ [7.429x10⁻³ moles] / [8.071x10⁻³ moles]

pH = 4.704

As initial pH was 5.000, change in pH is:

ΔpH = 5.000 - 4.740 = <em>0.296</em>

4 0
3 years ago
What happens to the energy that is lost when water freezes?
SVEN [57.7K]
<span>As we know through the principle of conservation of energy, energy can neither be created nor destroyed. Therefore, the energy removed from the water in order to make it freeze is absorbed by the surroundings. This is why the surroundings in which freezing is taking place are below freezing. This is more easily illustrated in the example of condensation. If you were to hold a plate over a pot of boiling water, some of the water would give its energy to the plate and condense on its surface.</span>
4 0
3 years ago
Read 2 more answers
How many mL of a 0.375 M solution can be made from 35 g of calcium phosphate?
andrew11 [14]

Answer:

300 mL

Explanation:

the unit formula of calcium phosphate is Ca3(PO4)2

molar mass of Ca3(PO4)2 = (3×40 + 2×31 + 8×16) g/mol = 310 g/mol

n = m/M = 35 g/(310 g/mol)

c = n/V

V = n/c = [35 g/(310 g/mol)]/0.375 mol/L

V = 0.30 L = 300 mL

3 0
2 years ago
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