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2 years ago

What is the pH of the solution obtained during the reaction of sodium with water? 1;3;7;14

Chemistry

2 answers:

Vesnalui [34]2 years ago

8 0

Answer:

Explanation:

The pH of a sodium chloride solution remains ≈7 due to the extremely weak basicity of the Cl− ion, which is the conjugate base of the strong acid HCl

Vadim26 [7]2 years ago

8 0

the alkali metals react with water produced hydrogen gas and the metal hydroxide

2Na(s) + 2H₂O(l) → 2NaOH(aq) + H₂(g)

NaOH : strong base, pH> 7

so the pH of the solution could be 14

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How many moles of H2O are in 64.0 g of H2O

Alina [70]

Answer:

Explanation:

stoichiometry of C₂H₂ to H₂O is 2:2.

Number of moles of C₂H₂ = molar mass of C₂H₂

Since the molar mass of C₂H₂ is 26 g/mol.

Number of C₂H₂ moles reacted = 64.0 g / 26 g/mol = 2.46 mol.

according to a molar ratio of 2:2.

the number of H₂O moles formed = a number of C₂H₂ moles reacted.

Therefore the number of H₂O moles produced = 2.46 mol

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2 years ago

What is another term for anode?

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Answer:positive electrode

Explanation:

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3 years ago

Which statement about enzymes is true?

Lelechka [254]

statement about enzymes that is correct is

b. they are large molecules that increase the rate of biologically important reactions

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so the correct answer is B.

7 0

3 years ago

Read 2 more answers

A solution is prepared by dissolving 318.6 g sucrose (C12H22O11) in 4905 g of water. Determine the molarity of the solution

alexandr1967 [171]

The molarity of sucrose solution is 0.19 M.

The molarity of HCl is 12.8 M.

<u>Explanation:</u>

a. Molarity can be found by finding its moles and volume of water in L and then dividing both(moles divided by volume in Litres).

Mass of sucrose = 318. 6 g

Molar mass of sucrose = 342.3 g/mol

Moles = $$\frac{mass}{molar mass}$

= $$\frac{318.6 g}{342.3 g/mol}$

= 0.93 moles

Mass of water = 4905 g

Density of water = 1000 g/L

Volume = $$\frac{mass}{density}$

= $$\frac{4905 g }{1000 g/L}$

= 4.905 L

Now we can find the molarity = $$\frac{moles}{Volume(L)}$

= $$\frac{0.93 moles}{4.905 L}$

= 0.19 M

So the molarity of sucrose solution is 0.19 M.

b. The molarity of HCl can be found as follows.

It is given that 39% HCl that means it contains 39 g of acid in 100 g of water.

Density of the solution is 1.20 g/mL, from this mass can be found as,

$$\frac{1 L \times 1000 mL \times 1.20 g}{1 L \times 1 mL}$

= 1200 g

Now we have to find out the amount of HCl in grams as,

$$\frac{1200g \times 39 g HCl }{100 g solution}$

= 468 g HCl

Now we have to find the number of moles,

moles = $$\frac{468 g}{36.46 g/mol}$

= 12.8 moles

Molarity of HCl = $$\frac{12.8 moles}{1 L }$

= 12.8 M

So the molarity of HCl is 12.8 M.

6 0

3 years ago

You titration 5.0 mL of HCl with 0.010 M NaOH. You find the end point of your titration occurs when 12.0 mL of NaOH has been add

Nookie1986 [14]

your answer is 0.00833M the volume was converted into liters

NaOH(aq)+HCl(aq)→NaCl(aq)+H2O(l)

Using the molarity equation, we can find the number of moles of HCl that reacted:

molarity=mol soluteL soln

mol solute=(molarity)(L soln)

mol HCl=(0.105molL)(0.0250L)=0.00263 mol HCl

(volume converted to liters)

Now, using the coefficients of the chemical reaction, we can determine the number of moles of NaOH that reacted:

0.00263mol HCl(1lmol NaOH1mol HCl)=0.00263 mol NaOH

Lastly, we'll use the molarity equation (using given volume of NaOH soln) again to determine the molarity of the sodium hydroxide solution:

molarity=mol soluteL soln

5 0

3 years ago