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2 years ago

Which of the following statements best describes why electrons

Chemistry

1 answer:

Lubov Fominskaja [6]2 years ago

5 0

Answer: Electons and protons have similar charges, and are therefore attracted to one another... I think

Explanation:

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(b) What is the pH of 0.40 M triethylammonium chloride, CH₃ (CH₂)₃ NHCl ?

Valentin [98]

pH of 0.40M triethylammonium chloride is 5.90.

A solution's acidity may be determined by looking at its pH, which is a measurement of hydrogen ion concentration. Pure water slightly separates into ions with roughly equal amounts of hydrogen and hydroxyl (OH) ions. [H+] is 107 for a neutral solution, or pH = 7.

<h3>Given : </h3>

Concentration of triethylammonium chloride = 0.40M

pH = ?

<h3>Solution: </h3>

(CH3CH2)3NHCl ------> (CH3CH2)3NH⁺ + Cl⁻

(CH3CH2)3NH⁺ will react with water to give H3O⁺ .

(CH3CH2)3N will have a Kb = 5.2 x 10 ^(-4)

Kw = Kb x Ka

=> Ka = Kw / Kb = 10^(-14) / 5.2 x 10 ^(-4)

=> Ka = 1.92 x 10^(-11)

so by the reaction we have ,

Ka = x²/(0.40 - x)

=> x = 1.2393 x 10 ^(-6)

now, pH = -log( [H3O⁺]) = - log ( 1.2393 x 10 ^(-6)) = 5.906

To learn more about pH :

brainly.com/question/15289741

#SPJ4

5 0

1 year ago

(6 points) Alice owns 20 grams of a radioactive isotope that has a half-life of ln(4) years. (a) Find an equation for the mass m

Cloud [144]

<u>Answer:</u> The equation to calculate the mass of remaining isotope is $[A]=\frac{20}{10^{-0.217t}}$

<u>Explanation:</u>

The equation used to calculate rate constant from given half life for first order kinetics:

$t_{1/2}=\frac{0.693}{k}$

where,

$t_{1/2}$ = half life of the reaction = $\ln 4=1.386yrs$

Putting values in above equation, we get:

$k=\frac{0.693}{1.386yrs}=0.5yrs^{-1}$

Rate law expression for first order kinetics is given by the equation:

$k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}$

where,

k = rate constant = $0.5yr^{-1}$

t = time taken for decay process

$[A_o]$ = initial amount of the sample = 20 grams

[A] = amount left after decay process = ? grams

Putting values in above equation, we get:

$0.5=\frac{2.303}{t}\log\frac{20}{[A]}$

$[A]=\frac{20}{10^{-0.217t}}$

Hence, the equation to calculate the mass of remaining isotope is $[A]=\frac{20}{10^{-0.217t}}$

6 0

3 years ago

In the reaction: CH3COO-+NH4+----------CH3COOH+NH3 what is the reactant acid and its conjugate base?

WINSTONCH [101]

Answer : The reactant acid and conjugate base in this reaction is, $NH_4^$ and $NH_3$ .

Explanation :

Conjugate acid : A species that is formed by receiving of a proton $(H^+)$ by a base is known as conjugate acid.

Conjugate base : A species that is formed by donating of a proton by an acid is known as conjugate base.

The given chemical reaction is,

$CH_3COO^-+NH_4^+\rightleftharpoons CH_3COOH+NH_3$

In this reaction, $CH_3COO^-$ (base) react with $NH_4^$ (acid) to give $CH_3COOH$ (conjugate acid) and $NH_3$ (conjugate base).

Therefore, the reactant acid and conjugate base in this reaction is, $NH_4^$ and $NH_3$ .

8 0

3 years ago

Be sure to answer all parts. Rubidium and bromine atoms are depicted at right. Answer the following questions. (a) What is the c

finlep [7]

The complete question is found on the image attached.

Answer:

a) Rb= +1, Br= -1

b)Bromide and rubidium ions are related to krypton

c) C

Explanation:

Rubidium is found in group 1 with a charge of +1. Bromine is found in group 17 with a charge of -1. Both species have the same configuration as krypton. The ionic sizes of the ions are a very similar to each other Rb+ is 166 while Be is 167.

This RbBr is an ionic compound.

6 0

3 years ago

Which describes the relationship between [H+] and [OH−] ?

jarptica [38.1K]

For a neutral solution,
[H+][OH-] = 1 x 10⁻¹⁴

7 0

3 years ago