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iren [92.7K]
2 years ago
13

Find the 22nd term of the arithmetic sequence whose common difference is d=5 and whose first term is a,=4.

Mathematics
2 answers:
Mars2501 [29]2 years ago
7 0

Answer:

109 is the 22nd term

Step-by-step explanation:

dedylja [7]2 years ago
3 0

Answer:

109

Step-by-step explanation:

a = 4

d = 5

a_{22} = a + 21d

a_{22} = 4 + 21(5)\\

a_{22} = 4 + 105

a_{22} = 109

hope you understood!

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7nadin3 [17]

So firstly, <u>the factor (4n - 5) cannot be further factored, so we will be focusing on 2n² + 5n + 3.</u>

So for this, we will be factoring by grouping. Firstly, what two terms have a product of 6n² and a sum of 5n? That would be 2n and 3n. Replace 5n with 2n + 3n:

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Next, factor 2n² + 2n and 3n + 3 separately. Make sure that they have the same quantity on the inside of the parentheses:

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Now we can rewrite this expression as<u> (2n+3)(n+1)(4n-5) , which is your final answer.</u>

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julia-pushkina [17]
<h2>Answer:  a = ¹/₂ (4 + b)</h2>

<h3>Step-by-step explanation:</h3>

To solve for 'a' we have to make it the subject of the equation. Since there are two unknowns ('a' & 'b'), we won't get a numerical value of 'a', but an expression in terms of the second unknown 'b'.

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                   a = ¹/₂ (4 + b)

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