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yuradex [85]
3 years ago
9

Example 4:

Mathematics
1 answer:
oee [108]3 years ago
3 0

Answer:

sorry but i need the points

Step-by-step explanation:

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Best known for its testing program, ACT, Inc., also compiles data on a variety of issues in education. In 2004 the company repor
GarryVolchara [31]

Answer:

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

Step-by-step explanation:

Check for conditions

For this case in order to use the normal distribution for this case or the 68-95-99.7% rule we need to satisfy 3 conditions:

a) Independence : we assume that the random sample of 400 students each student is independent from the other.

b) 10% condition: We assume that the sample size on this case 400 is less than 10% of the real population size.

c) np= 400*0.74= 296>10

n(1-p) = 400*(1-0.74)=104>10

So then we have all the conditions satisfied.

Solution to the problem

For this case we know that the distribution for the population proportion is given by:

p \sim N(p, \sqrt{\frac{p(1-p)}{n}})

So then:

\mu_p = 0.74

\sigma_p =\sqrt{\frac{0.74(1-0.74)}{400}}=0.0219

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

5 0
3 years ago
When Mya looked out at the store's parking lot, she noticed that for every 4 cars, there were 6 trucks. If there's a total of 22
olasank [31]

Answer:

<h2>88 cars</h2><h2>132 trucks</h2>

Step-by-step explanation:

This is a ratio problem, the ratio of  cars to trucks

for every 4 cars, there are 6 trucks

represented as a ratio we have 4:6

1. how many of them are cars

applying the part to whole strategy we have

4+6 = 10

let cars be x

\frac{4}{10}= \frac{x}{220}  \\\\x= \frac{220*4}{10} \\\\x= 880/10\\\\x= 88 cars

2.  how many of them are trucks?

let trucks be y

\frac{6}{10}= \frac{y}{220}  \\\\x= \frac{220*6}{10} \\\\y= 1320/10 \\\\y= 132 trucks

3 0
3 years ago
Item 8 Solve for x. Use the quadratic formula. 2x2−5x−9=0 Enter the solutions, in simplified radical form, in the boxes.
Lubov Fominskaja [6]

Answer:

5+√97/4

Also 5-√97/4

Step-by-step explanation:

The Quadratic formula is x=-b+-√b^2-4ac/2a

This means that we should plug the values for A B AND C into the formula

We can work out that

<u><em>A = 2</em></u>

<u><em>B=-5</em></u>

<u><em>C=-9</em></u>

Once we have put these into the formula we get

5+√97/4 (all over 4) aka 3.71

Also 5-√97/4 (all over 4) aka -1.21

7 0
3 years ago
Read 2 more answers
If a line segment is perpendicular to another line segment, it is the bisector of that line segment.
sp2606 [1]

False. Perpendicular lines run beside each other not through each other.

7 0
3 years ago
Please help not sure what to do
yawa3891 [41]

Answer:

3x12 theres 3 cirs and 6÷4 so 3x12

7 0
3 years ago
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