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3 years ago

Solve for X Solve for X Solve for X

Mathematics

2 answers:

nlexa [21]3 years ago

8 0

Answer:

<u>Opposite sides of the parallelogram are congruent</u>

<u /> $3x+4=16$ <u />

<u /> $3x=16-4$ <u />

<u /> $3x=12$ <u />

<u /> $x=12/3$ <u />

<u /> $x=4$ <u />

<h3><u>------------------------</u></h3><h3><u>hope it helps...</u></h3><h3><u>have a great day!!</u></h3>

yan [13]3 years ago

6 0

Answer: it is 4

Step-by-step explanation:

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mars1129 [50]

Answer:

$1.\:2^x=64, x=\boxed{6},\\2.\:x=\left(\frac{2}{3}\right)^3,x=\boxed{\frac{8}{125}}\\3.\:3\cdot (3^4)=3^x, x=\boxed{5}\\4.\:\frac{16}{25}=x^2,x=\boxed{\frac{4}{5}},$

Step-by-step explanation:

$1.\\\\2^x=64,\\\log 2^x=\log64,\\x\log 2=\log 64,\\x=\frac{\log 64}{\log 2}=\boxed{6}$

$2.\\x=\left(\frac{2}{5}\right)^3=\frac{2^3}{5^3}=\boxed{\frac{8}{125}}$

3. This problem incorporates an exponent property.

Exponent property used: $a^b\cdot a^c=a^{(b+c)}$ , yielding an answer of $\boxed{5}$

$4.\\\\\frac{16}{25}=x^2,\\x=\sqrt{\frac{16}{25}}=\frac{\sqrt{16}}{\sqrt{25}}=\boxed{\frac{4}{5}}$

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3 years ago

Read 2 more answers

Two sides of a triangle have lengths 10 and 18. Which inequalities describe the possible lengths for the third side x?

puteri [66]

Let with X is denoted the length of the third side.
For a triangle the following statements must be true:
The sum<span> of the </span>lengths<span> of any two sides of a </span>triangle<span> is greater than the </span>length<span> of the third side.
This means that this inequality can be written: X<10+18 ,X<28

</span>

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4 years ago

A car is moving with an initial velocity of 10 mph accelerates at the rate of a(t)=2.5t mph per second for 5 seconds. How fast i

Rom4ik [11]

Answer:

The car is going up at a speed of 22.5 mph

Step-by-step explanation:

In this question, we are asked to calculate the speed of a moving car which started moving at an initial velocity for a specific period of time.

To calculate this, we use one of the basic equations of motion;

v = u + at

Where v is the final velocity, u is the initial velocity and t is the time

From the question, we can identify the parameters as follows;

v = ?

u = 10mph

a = 2.5t mph per second for 5 seconds.

Hence a here would be 2.5 * 5 = 12.5

Now, let’s put these values in the equation

v = 10 + 12.5

v = 22.5 mph

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3 years ago

Read 2 more answers

Triangle angle-sum theorem <br> what is the value of u?

telo118 [61]

Answer:

u = ${\boxed{\sf{\: 3 \:}}}$ ⁰

Step-by-step explanation:

As we know that the sum of interior angles of triangle is 180⁰.

So, according to the question :

$\begin{gathered} \qquad{\longrightarrow{\sf{Sum \: of \: all \: angles = {180}^{\circ}}}}\\\\ \qquad{\longrightarrow{\sf{{74}^{\circ} + {52}^{\circ} + 18u = {180}^{\circ}}}}\\\\\qquad{\longrightarrow{\sf{{126}^{\circ} + 18u = {180}^{\circ}}}}\\\\\qquad{\longrightarrow{\sf{18u = {180}^{\circ} - {126}^{\circ}}}}\\\\\qquad{\longrightarrow{\sf{18u = {54}^{\circ}}}}\\\\\qquad{\longrightarrow{\sf{u = \dfrac{54}{8}}}}\\\\\qquad{\longrightarrow{\sf{u = {3}^{\circ}}}}\\\\ \qquad\star{\underline{\boxed{\frak{\pink{u = {3}^{\circ}}}}}}\end{gathered}$

Hence, the value of u is 3⁰.

$\rule{300}{2.5}$

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3 years ago

A lake contains 4 distinct types of fish. Suppose that each fish caught is equally likely to be any one of these types. Let Y de

strojnjashka [21]

Answer:

a) P(μ-k*σ≤ Y ≤ μ+k*σ ) ≥ 0.90

a= μ-3.16*σ , b= μ+3.16*σ

b) P(Y≥ μ+3*σ ) ≥ 0.90

b= μ+3*σ

Step-by-step explanation:

from Chebyshev's inequality for Y

P(| Y - μ|≤ k*σ ) ≥ 1-1/k²

where

Y = the number of fish that need be caught to obtain at least one of each type

μ = expected value of Y

σ = standard deviation of Y

P(| Y - μ|≤ k*σ ) = probability that Y is within k standard deviations from the mean

k= parameter

thus for

P(| Y - μ|≤ k*σ ) ≥ 1-1/k²

P{a≤Y≤b} ≥ 0.90 → 1-1/k² = 0.90 → k = 3.16

then

P(μ-k*σ≤ Y ≤ μ+k*σ ) ≥ 0.90

using one-sided Chebyshev inequality (Cantelli's inequality)

P(Y- μ≥ λ) ≥ 1- σ²/(σ²+λ²)

P{Y≥b} ≥ 0.90 → 1- σ²/(σ²+λ²)= 1- 1/(1+(λ/σ)²)=0.90 → 3= λ/σ → λ= 3*σ

then for

P(Y≥ μ+3*σ ) ≥ 0.90

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3 years ago