All categories

3 years ago

How do you factor 20x^5+54x^4+10x^3

Mathematics

1 answer:

allochka39001 [22]3 years ago

7 0

Answer:

2x^3(5x + 1) (2x + 5)

Step-by-step explanation:

I used a website called math.way, u should try it too!

You might be interested in

I need help. Please. Thank you.

Bond [772]

Answer:

Some answers include 42, 48, 54, etc.

Step-by-step explanation:

Since the number must be divisible by 2: the number must be even.

For a number to be divisible by 3, the sum of the digits must be divisible by 3.

4+2=6 which is divisible by 3

4+8=12 which is divisible by 3

5+4=9 which is divisible by 3

You can extend this logic for any number from 40 up to 99 since your number must be two digits and greater than 40.

If this helped, a brainliest would be greatly appreciated!

4 0

3 years ago

Read 2 more answers

Which of the following best describes the relationship shown in the equation below?

viva [34]

Answer:

C. this is not a functional relationship.

Step-by-step explanation:

In other words, for each x-value, there is only one corresponding y-value.

For the equation x2 + y2 = 10, find the y-value for a given x-value.

Let x = 1.

Since (-3) · (-3) = 9 and 3 · 3 = 9, there are two y-values for x = 1.

6 0

3 years ago

Salma wants to buy a new house but needs money for the down payment. Her parents agree to lend her money at an annual rate of 4%

DochEvi [55]

Answer:

Total Interest at the end of two years will be $320. She will owe a total repayment amount of $4000 plus $320 for a total of $4320.

Step-by-step explanation:

Hope this helps.

8 0

3 years ago

how to use Lcd in this problem? [a-2. -_1_ =_3_]find Lcd [ a+3 1 a-2]. (a+3)(a+2). multiply all neumerator to (LCD) a-2 - 1= 3 _

san4es73 [151]

It's not entirely clear to me what you're trying to solve, but it looks like the initial equation is

$\dfrac{a-2}{a+3} -1 = \dfrac3{a+2}$

First convert each term into a fraction with the same (i.e. the least common) denominator. The first term needs to be multiplied by a + 2; the second term by (a + 3) (a + 2); and the third term by a + 3 :

$\dfrac{a-2}{a+3}\cdot\dfrac{a+2}{a+2} -1\cdot\dfrac{(a+3)(a+2)}{(a+3)(a+2)} = \dfrac3{a+2}\cdot\dfrac{a+3}{a+3} \\\\ \dfrac{(a-2)(a+2)}{(a+3)(a+2)} - \dfrac{(a+3)(a+2)}{(a+3)(a+2)} = \dfrac{3(a+3)}{(a+3)(a+2)}$

Now that everything has the same denominator, we can combine the fractions into one. Move every term to one side and join the numerators:

$\dfrac{(a-2)(a+2)-(a+3)(a+2)-3(a+3)}{(a+3)(a+2)} = 0$

Simplify the numerator:

$\dfrac{(a^2-4)-(a^2+5a+6)-(3a+9)}{(a+3)(a+2)} = 0 \\\\ \dfrac{-8a-19}{(a+3)(a+2)} = 0$

If neither a = -3 nor a = -2, we can ignore the denominator:

$-8a-19 = 0$

Solve for a :

$-8a = 19 \\\\ \boxed{a = -\dfrac{19}8}$

4 0

3 years ago

The function f(x) = x] is graphed over the interval [-6, 3]. Which translation of the graph has the domain (-3, 6]? 0 A. g(x) =

bezimeni [28]

An interval graph in graphical theory is indeed an undirected graph formed by an interval set just on true line, with a top for every interval as well as an edge between vertex v to intersections. Graph intervals and these graphs are chordal graphs and graphs that are perfect, and the further discussion can be defined as follows:

Given:

$\bold{function\ f(x) = |x|}$