Answer:
23 gallons of water
Step-by-step explanation:
People use water to cook, clean, and drink every day. An estimate of 33.9% of the water used each day is for cooking. If a family uses 67.8 gallons of water a day for cooking, how many gallons do they use every day?
This is calculated as:
33.9 % × 67.8 gallons of water
= 0.339 × 67.8 gallons of water
= 22.9842 gallons of water
Approximately = 23 gallons of water
Therefore, 23 gallons of water are used everyday for cooking
Answers for A:
Factored form: (x-2)(x+4)
Zeros: x = 2, -4
Vertex: (-1, -9)
Answers for B:
Factored form: -(x+2)(x+7)
Zeros: x = -2, -7
Vertex: (-9/2, 25/4)
Answer:
The answer is 6 ratio because when you divide these two number then the anwer is 6
Y = -3(2) + 11
y = -6 + 11
y = 5
Answer is a) y = -3x + 11 , when x is 2 y is 5
Answer:


Step-by-step explanation:
Solve the following equation:
-In order to solve a pair of equations by using substitution, you first need to solve one of the equations for one of variables and then you would substitute the result for that variable in the other equation:
-First equation:

-Second equation:

-Choose one of the two following equations, which I choose the first one, then you solve for
by isolating

-Subtract
to both sides:

-Subtract
to both sides:


-Divide both sides by
:


-Multiply
by
:


-Substitute
for
in the second equation, which is
:


Multiply
by
:


-Combine like terms:


-Subtract
to both sides:


-Multiply both sides by
:


-After you have the value of
, substitute for
onto this equation, which is
:


-Multiply
and
:


-Since both
and
have the same denominator, then add the numerators together. Also, after you have added both numerators together, reduce the fraction to the lowest term:


