Answer:
The molar mass of N5O9
is 214.0245g/mol
Explanation:
To solve this problem, we need to know each number of mole of each element present in the compound
N has 5 moles
O has 9 moles
Then, we multiple each number of mole by its number of mass of each element present
N - 14.0067
O - 15.999
Multiplying by mole
N - 5 * 14.0067 = 70.0335
O - 9 * 15.999 = 143.991
Therefore,
Molar mass of N5O9 = 70.0335 + 143.991
= 214.0245g/mol
Answer:
Chemical properties would be like what you would make food with because you are changing the structure of the ingredients.
Physical properties would be like a chair or the device you asked this question on.
Explanation:
Answer:The endpoint does not correspond exactly to the equivalence point
At the endpoint, a change in a physical quantity associated with the equivalence point occurs.
At the equivalence point, the mole number of equivalents of reagent added is equal to the mole number of equivalents of analyte present.
Explanation:
The end point is always indicated by some physical property that changes such as colour. At the equivalence point, the mole number of equivalents of reagent added is equal to the mole number of equivalents of analyte present. The equivalence point cannot be physically observed but can be deduced after a titration curve is plotted.
Answer:
A. 20.866%
Explanation:
First, we calculate molar mass of Li3PO3
Molar mass of Li3PO3 = 6.9 (3) + 31 + 16(3)
= 20.7 + 31 + 48
= 99.7g/mol
To calculate the percent composition of Lithium, we say:
Mass of lithium in compound/mass of compound × 100
% composition = 20.7/99.7 × 100
= 0.208 × 100
= 20.8%.
