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pishuonlain [190]
3 years ago
9

The physical properties of matter produce many cause and effect relationships. Which effort is produced by the close packing of

molecules in a solid?
A. decreased compressibility
B. increased compressibility
C. Increased motion of molecules
D. increased kinetic energy​
Chemistry
1 answer:
stepan [7]3 years ago
4 0

Answer:

A.

Explanation:

We know quite well that there are three states of matter. Solid,liquid and gaseous states.

While the gaseous states gives the highest freedom of movement, the solid state gives the least freedom of movement. Molecules and atoms of a solid are so tightly packed.

This makes them very dense as they are held together by strong intermolecular forces of attraction. These strong forces prevents the movement of the particles.

As these particles are strongly attracted towards each other, they tend to be incompressible.

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It’s a physical change

Explanation:

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Write 0.000443200 to two significant figures
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0.00044


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Whats Potassium bond type? Please help!
olga_2 [115]

Answer:

A metallic bond.

Explanation:

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Hope this helped!

5 0
3 years ago
Read 2 more answers
Which list correctly compares how adding energy affects a substance during a phase change and not during a phase change?(1 point
Crank

Answer:

1) during a phase change: particles overcome forces of attraction and temperature stays the same not during a phase change: temperature rises 2)Particle motion decreases, and electrostatic forces pull particles closer together.

3) Gases fill their container, showing that gas particles are not tied together and can move far apart.

Explanation:

3 0
2 years ago
How to solve for K when given your anode and cathode equations and voltage
Aleks04 [339]

Answer:

See Explanation

Explanation:

In thermodynamics theory the Free Energy (ΔG) of a chemical system is described by the expression ΔG = ΔG° + RTlnQ. When chemical system is at equilibrium ΔG = 0. Substituting into the system expression gives ...

0 = ΔG° + RTlnKc, which rearranges to ΔG° = - RTlnKc.  ΔG° in electrochemical terms gives ΔG° = - nFE°, where n = charge transfer, F = Faraday Constant = 96,500 amp·sec and E° = Standard Reduction Potential of the electrochemical system of interest.

Substituting into the ΔG° expression above gives

-nFE°(cell) = -RTlnKc => E°(cell) = (-RT/-nF)lnKc = (2.303·R·T/n·F)logKc

=> E°(cell) = (0.0592/n)logKc = E°(Reduction) - E°(Oxidation)

Application example:

Calculate the Kc value for a Zinc/Copper electrochemical cell.

Zn° => Zn⁺² + 2e⁻  ;    E°(Zn) = -0.76 volt  

Cu° => Cu⁺² + 2e⁻ ;    E°(Cu) =  0.34 volt

By natural process, charge transfer occurs from the more negative reduction potential to the more positive reduction potential.

That is,

           Zn° => Zn⁺² + 2e⁻ (Oxidation Rxn)

Cu⁺² + 2e⁻ => Cu°             (Reduction Rxn)

E°(Zn/Cu) = (0.0592/n)logKc

= (0.0592/2)logKc = E°(Cu) - E°(Zn) = 0.34v - (-0.76v) = 1.10v

=> logKc = 2(1.10)/0.0592 = 37.2

=> Kc = 10³⁷°² = 1.45 x 10³⁷

3 0
3 years ago
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