Answer:
The pOH of HNO₃ solution that ha OH⁻ concentration 9.50 ×10⁻⁹M is 8.
Explanation:
Given data:
[OH⁻] = 9.50 ×10⁻⁹M
pOH = ?
Solution:
pOH = -log[OH⁻]
Now we will put the value of OH⁻ concentration.
pOH = -log[9.50 ×10⁻⁹M]
pOH = 8
Thus the pOH of HNO₃ solution that ha OH⁻ concentration 9.50 ×10⁻⁹M is 8.
Answer:
Volume = 10ml
Density = 1/5 g/ml or 0.20g/ml
Explanation:
The rocks are 10ml since the initial volume went up by 10.
Since density = mass/volume, you divide 2 by 10.
D = 2/10
D = 1/5 g/ml or 0.20g/ml
(Unit is g/ml aka grams/millileter)
False. An increase in temperature is an exothermic reaction. However, when a temperature decreases this is known as an endothermic reactionz
Answer:
The answer to your question is: 0.25 l
Explanation:
Data
P1 = 1 atm
V1 = 0.5 l
P2 =2 atm
V2 = ?
T = constant
Formula
V1P1 = V2P2
Clear V2 from the formula
V2 = V1P1/P2
Substitution
V2 = (0.5)(1)/2 substitution
= 0.25 l result
Period are going left to right across the periodic table
Groups are going up to down on the periodic table
