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MissTica
3 years ago
10

Why were atoms deflected in rutherfords gold foil experiments?

Chemistry
1 answer:
Usimov [2.4K]3 years ago
3 0
Most of the atoms were made up of empty space
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A plant was placed in the corner of a room away from a window. What might you observe about the plant after five days?
DIA [1.3K]

Answer:

1. A. The plant leans toward window.

Explanation:

Plants need light to perform photosynthesis and live. Therefore, this means the plant will always lean toward light in order to survive.

- Hope that helps! Please let me know if you need further explanation.

8 0
3 years ago
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Select the electron-domain geometry for a molecule with three bonding domains and one nonbonding domain.
mamaluj [8]

Answer: C) Tetrahedral

Explanation:

The number of electron pairs is 4 that means the hybridization will be sp^3 but as there are three bonding domains and one nonbonding domain, thus electronic geometry is tetrahedral and the molecular geometry will be trigonal pyramidal.

Linear electron geometry is possible when number of electron pairs is 2 and the hybridization will be sp^2.

Trigonal planar geometry is possible when number of electron pairs is 3 and the hybridization will be sp^3.

Trigonal bipyramidal geometry is possible when number of electron pairs is 5 and the hybridization will be sp^3d.

Octahedral geometry is possible when number of electron pairs is 6 and the hybridization will be sp^3d^2.

6 0
3 years ago
Which of the following represents the atomic number of an element?
Anna11 [10]

Answer:

The atomic number is the number of protons in the nucleus

4 0
2 years ago
What do a mole of magnesium (Mg) and a mole of iron (Fe) have in common?
azamat
What they have in common is that they both have the same number of atoms.
9 0
3 years ago
Under certain conditions Argon gas diffuses at a rate of 3.2 cm per second under the same conditions an unknown gas diffuses at
kozerog [31]

Answer:

20 g/mol

Explanation:

We can use <em>Graham’s Law of diffusion</em>:

The rate of diffusion (<em>r</em>) of a gas is inversely proportional to the square root of its molar mass (<em>M</em>).

r = \frac{1 }{\sqrt{M}}

If you have two gases, the ratio of their rates of diffusion is

\frac{r_{2}}{r_{1}} = \sqrt{\frac{M_{1}}{M_{2}}}

Squaring both sides, we get

(\frac{r_{2}}{r_{1}})^{2} = \frac{M_{1}}{M_{2}}

Solve for <em>M</em>₂:

M_{2} = M_{1} \times (\frac{r_{1}}{r_{2}})^{2}

M_{2} = \text{39.95 g/mol} \times (\frac{\text{3.2 cm/s}}{\text{4.5 cm/s}})^{2}= \text{39.95 g/mol} \times (0.711 )^{2}

= \text{39.95 g/mol} \times 0.506 = \textbf{20 g/mol}

7 0
3 years ago
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