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dusya [7]
3 years ago
6

In a certain chemical reaction, 297 g of zinc chloride was produced from the single replacement reaction of excess zinc and 202.

7 g of lithium chloride. What is the percent yield of zinc chloride?
Chemistry
1 answer:
poizon [28]3 years ago
8 0

Hey katie :

Molar mass of LiCl = 42.4 g/mol

Number of mole of LiCl = (given mass)/(molar mass)

= 202.7/42.4  => 4.78 moles of LiCl

Reaction taking place  is  :

2LiCl  +  Zn   -- >  ZnCl2   +   2Li

according to reaction :

2 mole of LiCl give 1 mole of ZnCl2

1 mole of LiCl give 1/2 mole of ZnCl2

4.78 mole of LiCl give (1/2)*4.78 mole of ZnCl2

number of mole of ZnCl2 formed = 2.39 moles

molar mass of ZnCl2 = 136.3 g/mol

mass of ZnCl2 formed = (number of moles of ZnCl2)*(molar mass)

= 2.39*136.3

= 325.8 g of ZnCl2

%yield = {(actual yiield)/(theoretical yield)}*100

= (297/325.8)*100

= 91.2 %

Answer : 91.2%

Hope that helps!

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A compound containing sodium, chlorine, and oxygen is 25.42% sodium by mass. A 3.25 g sample gives 4.33×1022 atoms of oxygen. Wh
Tcecarenko [31]
step  one 
calculate  the  %  of  oxygen
from  avogadro  constant
1moles =  6.02  x  10  ^23  atoms
what  about    4.33  x10^22  atoms
= ( 4.33  x  10^ 22 x 1 mole )  /  6.02  10^23=   0.0719 moles
mass=  0.0719  x16=  1.1504   g
% composition   is therefore= ( 1.1504/3.25)  x100 = 35.40%
 step  two
calculate the  %  composition  of  chrorine
100-  (25.42  +  35.40)=39.18%

step  3
calculate the  moles   of  each  element
that   is  
Na  =  25.42  /23=1.1052  moles
Cl=  39.18  /35.5=1.1037moles
O=  35.40/16=  2.2125   moles
step  4
find  the  mole  ratio  by  dividing  each  mole  by  1.1037  moles
that  is
Na  =  1.1052/1.1037=1.001
Cl= 1.1037/1.1037=  1
0=2.2125 = 2
therefore  the  empirical  formula= NaClO2
8 0
3 years ago
Please help me for question 1 and 2
likoan [24]

Answer:-

1) 6 mol

2) Mo

Explanation: -

Mass of Ozone = 48 g

Chemical formula of ozone = O3

Molar mass of Ozone O 3 = 16 x 3 = 48 g mol-1

Number of moles of ozone = Mass / molar mass

= 48 g / 48 g mol-1

= 1 mol

According to Avogadro’s law, 1 mole of a substance has 6.02 x 10^ 22 molecules.

So 1 mol of O3 has 6.02 x 10^ 22 molecules of ozone.

Now each Ozone molecule has 3 atoms of oxygen.

So, 1 mol of ozone has 3 x 6.02 x 10^22 atoms of oxygen.

Sodium must have 2 x 3 x 6.02 x 10^22 atoms as per the question.

According to Avogadro’s law, 6.02 x 10^ 22 atoms are in 1 mol of sodium

So, for 2 x 3 x 6.02 x 10^22 atoms, there should be (1/ 6.02 x 10^ 22) x 2 x 3 x 6.02 x 10^22

= 6 mol of sodium.

b)

Let the mass of M be m g

Formula of hexafluoride = MF6.

Mass of the hexafluoride = g + 6 x 19

= m + 114

Mass of M=0.250g

Moles of M = 0.250/m

Mass of MF6= 0.547g

Moles of MF6 = 0.547/ (m + 114)

We know 1 mole of M gives 1 mole of MF6.

0.250/m moles of M gives 0.250/m moles of MF6.

But number of moles of MF6 = 0.547/ (m + 114)

Thus

0.250/m = (0.547)/ (m +114))

0.250m + 0.250 x 114 = 0.547m

m = 0.250 x 114 / (0.547 -0.250)

= 96

We see from the given data that Mo is 96.

So M is Mo.

4 0
3 years ago
The human body can get energy by metabolizing proteins, carbohydrates or fatty acids, depending on the circumstances. Roughly sp
Kamila [148]

Answer:

the ratio of the energy the body gets metabolizing each gram of alanine to the energy the body gets metabolizing each gram of glucose is 1.0111

Explanation:

Given the data in the question;

To determine the ratio of the energy the body gets metabolizing each gram of alanine to the energy the body gets metabolizing each gram of glucose, first we get the molar masses of both alanine and glucose

we know that;

Molar mass of alanine ( C₃H₇NO₂ ) = 89.09 g/mol

Molar mass of glucose ( C₆H₁₂O₆ ) = 180.16 g/mol

now, { metabolizing each gram }

moles of alanine = mass taken / molar mass

= 1g / 89.09 g/mol = 1/89.09 moles

moles of glucose = mass taken / molar mass

= 1g / 180.16 g/mol = 1/180.16 moles

In each molecule of alanine, we have 3 atoms  of carbon.

Also, in each molecules of glucose, we have 6 atoms of carbon

so,

number of moles of Carbons in alanine = 3 × 1/89.09 moles = 0.03367

number of moles of Carbons in glucose = 6 × 1/180.16 moles = 0.0333

so ratio of energy will be the ratio of carbon atoms, which is;

⇒ 0.03367 / 0.0333 = 1.0111

Therefore, the ratio of the energy the body gets metabolizing each gram of alanine to the energy the body gets metabolizing each gram of glucose is 1.0111

7 0
3 years ago
sample of atmospheric gas collected at an industrial site is stored in a 250 mL amber glass bottle that has a pressure of 1.02 a
Nady [450]

Answer:- New pressure is 0.942 atm.

Solution:- The volume of the glass bottle would remain constant here and the pressure will change with the temperature.

Pressure is directly proportional to the kelvin temperature. The equation used here is:

P_1T_2=P_2T_1

Where, T_1 and T_2 are initial and final temperatures, P_1 and P_2 are initial and final pressures.

T_1 = 20.3 + 273.15 = 293.45 K

T_2 = -2.0 + 273.15 = 271.15 K

P_1 = 1.02 atm

T_2  = ?

Let's plug in the values in the equation and solve it for final pressure.

1.02atm(271.15K)=P_2(293.45K)

P_2=\frac{1.02atm*271.15K}{293.45K}

P_2 = 0.942 atm

So, the new pressure of the jar is 0.942 atm.


5 0
4 years ago
Perform the following operation
lukranit [14]

Answer:

(5.4 x 10³) x (1.2 x 10⁷) = 6.48 x 10¹⁰

With correct significant figures, the answer would be 6.5 x 10¹⁰.

4 0
2 years ago
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