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dusya [7]
3 years ago
6

In a certain chemical reaction, 297 g of zinc chloride was produced from the single replacement reaction of excess zinc and 202.

7 g of lithium chloride. What is the percent yield of zinc chloride?
Chemistry
1 answer:
poizon [28]3 years ago
8 0

Hey katie :

Molar mass of LiCl = 42.4 g/mol

Number of mole of LiCl = (given mass)/(molar mass)

= 202.7/42.4  => 4.78 moles of LiCl

Reaction taking place  is  :

2LiCl  +  Zn   -- >  ZnCl2   +   2Li

according to reaction :

2 mole of LiCl give 1 mole of ZnCl2

1 mole of LiCl give 1/2 mole of ZnCl2

4.78 mole of LiCl give (1/2)*4.78 mole of ZnCl2

number of mole of ZnCl2 formed = 2.39 moles

molar mass of ZnCl2 = 136.3 g/mol

mass of ZnCl2 formed = (number of moles of ZnCl2)*(molar mass)

= 2.39*136.3

= 325.8 g of ZnCl2

%yield = {(actual yiield)/(theoretical yield)}*100

= (297/325.8)*100

= 91.2 %

Answer : 91.2%

Hope that helps!

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The pH of the buffer is 6.1236.

Explanation:

The strength of any acid solution can be obtained by determining their pH. Even the buffer solution strength of the weak acid can be determined using pH. As the dissociation constant is given, we can determine the pKa value as the negative log of dissociation constant value.

pKa=-log[H] = - log [ 5.66 * 10^{-7}]\\ \\pka = 7 - log (5.66)=7-0.753=6.247\\\\pka = 6.247

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Hey there!

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