<u>Hint </u><u>:</u><u>-</u>
- Break the given sequence into two parts .
- Notice the terms at gap of one term beginning from the first term .They are like
. Next term is obtained by multiplying half to the previous term . - Notice the terms beginning from 2nd term ,
. Next term is obtained by adding 3 to the previous term .
<u>Solution</u><u> </u><u>:</u><u>-</u><u> </u>
We need to find out the sum of 50 terms of the given sequence . After splitting the given sequence ,
.
We can see that this is in <u>Geometric</u><u> </u><u>Progression </u> where 1/2 is the common ratio . Calculating the sum of 25 terms , we have ,
Notice the term
will be too small , so we can neglect it and take its approximation as 0 .

Now the second sequence is in Arithmetic Progression , with common difference = 3 .
![\implies S_2=\dfrac{n}{2}[2a + (n-1)d]](https://tex.z-dn.net/?f=%5Cimplies%20S_2%3D%5Cdfrac%7Bn%7D%7B2%7D%5B2a%20%2B%20%28n-1%29d%5D%20)
Substitute ,
![\implies S_2=\dfrac{25}{2}[2(4) + (25-1)3] =\boxed{ 908}](https://tex.z-dn.net/?f=%5Cimplies%20S_2%3D%5Cdfrac%7B25%7D%7B2%7D%5B2%284%29%20%2B%20%2825-1%293%5D%20%3D%5Cboxed%7B%20908%7D%20)
Hence sum = 908 + 1 = 909
Answer:
answer is 19.
Step-by-step explanation:
see picture for explanation.
hope it helps you.
Answer:
P( x = 2) = 0.4
Or 40%
Step-by-step explanation:
Given that wildcat has 0.5 probability of winning if they play nine times
Probability = possible outcomes ÷ required outcome
The required outcome = 9
Probability = 0.5
Let calculate the possible outcomes
Possible outcomes = 0.5 × 9 = 4.5 games
the probability that the Wildcats win two of the games will be
P( x = 2) = 2/4.5 = 0.44
Or 44%
We can use the equation:
f = 3.25s
3.25 is the cups of flour used for every cup of sugar.
Where 'f' represents flour and 's' represents sugar.
Given :
Amount, A = 5760 Rs.
Interest in the amount, I = 1526 Rs.
To Find :
We need to find the % rate of interest.
Solution :
Let, us assume it is simple interest.
So,

Hence, this is the required solution.