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kozerog [31]
3 years ago
9

HURRY PLEASE DUE AT 9:00 AM PLEASE

Mathematics
1 answer:
GalinKa [24]3 years ago
3 0

Answer:

24(x+2)

Step-by-step explanation:

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Solve for x. 9^x+15=3^7x
Art [367]

The solution is x = 6

Step-by-step explanation:

Let us revise some rules of the exponents

  • If a^{n}=a^{m} , then n = m
  • (a^{n})^{m}=a^{nm}

∵ 9^{(x+15)}=3^{7x}

∵ 9 = 3 × 3

∴ 9 = 3²

- Substitute 9 by 3² in the equation above

∴ (3^{2})^{(x+15)}=3^{7x}

- Use the second rule above for the left hand side

∵ (3^{2})^{(x+15)}=3^{2(x+15)}

∴ (3^{2})^{(x+15)}=3^{2x+30}

∴ 3^{2x+30}=3^{7x}

- By using the first rule above

∴ 2x + 30 = 7x

- Subtract 2x from both sides

∴ 30 = 5x

- Divide both sides by 5

∴ 6 = x

The solution is x = 6

Learn more:

You can learn more about solving equations in brainly.com/question/7153188

#LearnwithBrainly

3 0
3 years ago
How do you do this question?
mr_godi [17]

Answer:

None of the above

Step-by-step explanation:

According to the divergence test, if the limit of a sequence as n approaches infinity does not equal 0, then the series diverges.  (Notice that if the limit does equal 0, the series doesn't necessarily converge).

According to the geometric series test, a geometric series converges if -1 < r < 1, and diverges otherwise.

The first series is a geometric series with r = -5/3.  So it diverges.

The second series is also a geometric series:

3ⁿ⁻¹ / 2ⁿ = ⅓ (3ⁿ / 2ⁿ) = ⅓ (3/2)ⁿ

r = 3/2, so it diverges.

For the third series, the limit as n approaches infinity equals 1.  This fails the divergence test, so this series also diverges.

For the fourth series, the limit as n approaches infinity equals 1.  This fails the divergence test, so this series also diverges.

5 0
3 years ago
Need the answer asap!!!!! 63 points!!!!
nekit [7.7K]

Answer:

A

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
A simple random sample of 125 SAT scores has a mean of 1522. Assume that SAT scores have a population standard deviation of 335.
Fed [463]

Answer:

1463.3\:

Step-by-step explanation:

Since the population standard deviation \sigma, is known, we use the z confidence interval for the mean.

This is given by:

\bar X-z_{\frac{\alpha}{2} }(\frac{\sigma}{\sqrt{n} } )\:

For a 95% confidence interval we use z=1.96.

It was also given that: n=125, \bar X=1522 and \sigma=335

Let us substitute the values to get:

1522-1.96(\frac{335}{\sqrt{125} } )\:

1463.3\:

<u>Interpretation:</u>

We can say with 95% confidence that the interval between 1463.3 and 1580.7 SAT scores contains the population mean based on the sample 125 SAT scores.

7 0
3 years ago
Which ecpression is equivalent to sqrt 8x^7y^8?
mars1129 [50]

Domain:\ x\geq0\ \wedge\ y\in\mathbb{R}

\sqrt{8x^7y^8}=\sqrt8\cdot\sqrt{x^7}\cdot\sqrt{y^8}=\sqrt{4\cdot2}\cdot\sqrt{x^6\cdot x}\cdot\sqrt{y^{4\cdot2}}\\\\=\sqrt4\cdot\sqrt2\cdot\sqrt{x^6}\cdot\sqrt{x}\cdot\sqrt{(y^4)^2}=2\sqrt2\cdot\sqrt{x^{3\cdot2}}\cdot\sqrt{x}\cdot y^4\\\\=2y^4\sqrt2\cdot\sqrt{(x^3)^2}\cdot\sqrt{x}=2y^4\sqrt{2x}\cdot x^3\\\\=\boxed{2x^3y^4\sqrt{2x}}

Used:\\\\\sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\\sqrt{a^2}=a\ for\ a\geq0

7 0
4 years ago
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