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kumpel [21]
3 years ago
15

Please help!! ASAP!!

Mathematics
2 answers:
labwork [276]3 years ago
6 0

Answer:

jhb iunohiuhbiuohijhiuoniu8bkiujb

Step-by-step explanation:

klemol [59]3 years ago
4 0

Answer:

47.56

Step-by-step explanation:

i know

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Any one 100% kno these two answers
liubo4ka [24]
Answer:

The first question would likely be y=10.
The second question would likely be x=20.
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2 years ago
A research center poll showed that 76​% of people believe that it is morally wrong to not report all income on tax returns. What
Tanya [424]
You would subtract 0.76 from 100 and your answer will be 99.24
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3 years ago
Which of the following ordered pairs satisfy the equation y=5x-1
vazorg [7]

Answer:

jsjajsjhshssh

y = 5x - 1

hwshhsch

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2 years ago
Read 2 more answers
Prove the equation (2x+5)2 = 4x (x + 5) +25
shtirl [24]

Answer:  x = -5/2 and x = -3/2

Step-by-step explanation:

(2x + 5)2 = 4x (x + 5) +25

   4x + 10 = 4x² + 20x + 25

   [minus 4x on both sides.]

            10 = 4x² + 16x + 25

   [minus 10 on both sides.]

            0 = 4x² + 16x + 15

ac = 4(15) = 60,then find the factors that add up to 16, which is 6 and 10.

            0 = 4x² + 6x + 10x + 15

            0 = 2x(2x + 3) + 5(2x + 3)

            0 = (2x + 5)(2x + 3)

2x + 5 = 0                                 2x + 3 = 0

       2x = -5                                    2x = -3

         x = -5/2                                    x = -3/2

3 0
2 years ago
Read 2 more answers
(a) Let {A1, A2} be a partition of a sample space and let B be any event. State and prove the Law of Total Probability as it app
Nataliya [291]

Answer:

0.625

Step-by-step explanation:

Given that {A1, A2} be a partition of a sample space and let B be any event. State and prove the Law of Total Probability as it applies to the partition {A1, A2} and the event B.

Since A1 and A2 are mutually exclusive and exhaustive, we can say

b) P(B) = P(A1B)+P(A2B)

Selecting any one coin is having probability 0.50. and A1, A2 are events that the coins show heads.P(B/A1) = 0.50 \\P(B/A2) = 0.75\\P(A1B) = 0.5(0.5) = 0.25 \\P(A2B) = 0.75(0.5) = 0.375\\P(B) = 0.625

c) Using Bayes theorem

conditional probability that it wasthe biased coin

=\frac{0.375}{0.625} \\=\frac{3}{5}

d) Given that the chosen coin flips tails,the conditional probability that it was the biased coin=\frac{0.25*0.5}{0.25*0.5+0.5*0.5} \\=\frac{1}{3}

7 0
2 years ago
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