Atomic mass of boron = 10.81
<h3>What are Isotopes?</h3>
Isotopes are variants of a particular element in which they have the same number of protons but differ in the number of neutrons in the atom.
So, here as we said we have isotopes which weigh 10.01 and 11.01.
Given,
relative abundance of B-10 = 10.1 amu
relative abundance of B- 11 = 11.01 amu
percentage of B-10 = 20%
percentage of B-11 = 80%
Then the relative atomic mass depends upon the relative abundance of various isotopes of that particular element. Suppose an element consists of two isotopes and average atomic mass is equal to
(Relativeabundance(1)×Atomicmass(1)+Relativeabundance(2)×Atomicmass(2)) / (Relativeabundance(1)+Relativeabundance(2))
Atomic mass of boron = (20 × 10.01 + 80 × 11.01) / (80 + 20 )
= 1081/100
= 10.81
To learn more about atomic mass from the given link
brainly.com/question/3187640
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It splits into two equal nuclei of approx. equal mass.
Answer:
0.9875 mole O₂
Explanation:
Rxn => H₂ + ¹/₂O₂ => H₂O
from above reaction, 1 mol H₂ requires ¹/₂ mol O₂ then 1.975 mol H₂ requires ¹/₂(1.975 mol)O₂ or 0.9875 mol O₂.
Answer:
I2 + 2S2O3^2- --------> S4O6^2- + 2I^-
Explanation:
The correct equation is;
2Na2S2O3 + I2 → Na2S4O6 + 2NaI
Oxidation half equation;
2S2O3^2- --------> S4O6^2- + 2e-
Reduction half equation;
I2 + 2e ----------> 2I^-
Overall balanced redox reaction equation;
I2 + 2S2O3^2- --------> S4O6^2- + 2I^-
