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Tems11 [23]
3 years ago
13

Write a chemical equation showing how this is an acid according to the arrhenius definition. express your answer as a balanced c

hemical equation. identify all of the phases in your answer.h2so4
Chemistry
1 answer:
Alik [6]3 years ago
7 0

According to Arrhenius theory, acid is a substance that releases H⁺ ions when dissolved in water.

In order to apply this theory, the substance must be soluble in water.

H₂SO₄ is highly soluble in water. It undergoes following dissociation reaction when dissolved in water.

H_{2}SO_{4}(aq)\overset{H_{2}O}{\rightarrow} 2H^{+}(aq)+ SO_{4}^{2-}(aq)

From the above equation, we can see that H₂SO₄ forms 2 H⁺ ions when dissolved in water. Therefore it behaves as an acid according to Arrhenius theory.

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4HF(g)+SiO2(s)→SiF4(g)+2H2O(l)
Alecsey [184]
<span>Gallium-72 that is what i got when i did the math for it</span>
8 0
3 years ago
Answers: A-5N B-6N C-7N D-8N
Misha Larkins [42]

Answer:

<h3>A-5N B-6N C-7N D-8N</h3>

Explanation:

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5 0
3 years ago
Which of the following gases is the best choice for inflating a balloon that must remain inflated for a long period of time?
Oliga [24]

Answer:

argon

Explanation:

argon inhibits evaporation, and prevents corrosion

6 0
3 years ago
WILL MARK BRANILEST
ahrayia [7]

Answer:

FeCl3 is the limiting reactant

O2 is in excess

Theoretical yield Cl2 = 9.84 grams

The % yield is 96.5 %

Explanation:

Step 1: Data given

Mass of FeCl3 = 15.0 grams

Moles O2 = 4.0 moles

Mass of Cl2 produced = 9.5 grams

Step 2: The balanced equation

4FeCl3 + 3O2 → 2Fe2O3 + 6Cl2

Step 3: Calculate moles FeCl3

Moles FeCl3 = mass FeCl3 / molar mass FeCl3

Moles FeCl3 = 15.0 grams / 162.2 g/mol

Moles FeCl3 = 0.0925 moles

Step 4: Calculate limiting reactant

FeCl3 is the limiting reactant. Because we have way more (more than ratio 3:4) moles O2 than FeCl3. It will completely be consumed (0.0925 moles). O2 is in excess. There will react = 0.069375 moles O2

There will remain 4.0 - 0.069375 = 3.930625 moles

Step 5: Calculate moles Cl2

For 4 moles FeCl3 we need 3 moles O2 to produce 2 moles Fe2O3 and 6 moles Cl2

For 0.0925 moles FeCl3 moles we'll have 6/4 * 0.0925 = 0.13875 moles Cl2.

Step 6: Calculate mass Cl2

Mass Cl2 = moles * molar mass

Mass Cl2 = 0.13875 moles * 70.9 g/mol

Mass Cl2 = 9.84 grams

Step 7: Calculate % yield

% yield = (actual yield / theoretical yield) * 100%

% yield = (9.5 grams / 9.84 grams ) * 100%

% yield = 96.5 %

The % yield is 96.5 %

4 0
3 years ago
A wood pole is 12 metres long and is cut into 5 equal sections. If each cut wastes 10 cm of pole, what length would each section
Sophie [7]

Each section would be 230 centimeters or 2.30 meters long.

<h3>Sectional division</h3>

The original wood pole is 12 meters long.

12 meters = 12 x 100 = 1200 centimeters

It is to be cut into 5 equal sections: 1200/5 = 240 centimeters

But each cut wastes 10 cm of the pole.

          240 - 10 = 230 centimeters.

Thus, each section would be 230 centimeters or 2.30 meters long.

More on sectional divisions can be found here: brainly.com/question/15381501

#SPJ1

6 0
2 years ago
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