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kari74 [83]
3 years ago
10

What is the solution set for this linear-quadratic system of equations?

Mathematics
1 answer:
Ilya [14]3 years ago
7 0
(4,0) (o,3) 1727/!/818281
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40 percent of 112.5%
lord [1]
First 112% is 1.12 divide it by 100 to get .0112 then mutiply it by 40 to get .448 so .448 is the answer. Hope this helps.
7 0
3 years ago
Find the midpoint of the segment with the following endpoints.<br> (4,2) and (7,6)
Tema [17]

Answer:

The answer is

<h2>( \frac{11}{2} \: , \: 4)</h2>

Step-by-step explanation:

The midpoint M of two endpoints of a line segment can be found by using the formula

M = (  \frac{x1 + x2}{2} , \:  \frac{y1 + y2}{2} )

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(4,2) and (7,6)

The midpoint is

M = ( \frac{4 + 7}{2}   \: , \:  \frac{2 + 6}{2} ) \\  = ( \frac{11}{2} \: , \:  \frac{8}{2} )

We have the final answer as

( \frac{11}{2} \: , \: 4)

Hope this helps you

4 0
3 years ago
How do ypu find the area of 1/4 of a circle?
julia-pushkina [17]
First find the area of the circle then divide it by 4
6 0
3 years ago
Multiply 2 5/8 and -2 3/5
Rina8888 [55]

Answer:

-6 33/40

Step-by-step explanation:

2 5/8  * -2 3/5

Change each to an improper fraction

2 5/8 = (8*2+5)/8 = 21/8

2 3/5 = (5*2+3)/5 = 13/5

21/8 * -13/5

-273/40

Change to mixed number

40 goes into 273 6 times

6*40 = 240   273-240 =33

-6 33/40

8 0
3 years ago
You are an assistant director of the alumni association at a local university. You attend a presentation given by the university
NNADVOKAT [17]

Answer:

(0.102, -0.062)

Step-by-step explanation:

sample size in 2018 = n1 = 216

sample size in 2017 = n2 = 200

number of people who went for another degree in 2018 = x1 = 54

number of people who went for another degree in 2017 = x2 = 46

p1 = x1/n1 = 0.25

p2 = x2/n2 = 0.23

At 95% confidence level, z critical = 1.96

now we have to solve for the confidence interval =

<h2> p1 -p2 ± z*\sqrt{((1-p1)*p1)/n1 + ((1-p2)*p2/n2}</h2>

0.25 -0.23 ± 1.96*\sqrt{((1 - 0.25) * 0.25)/216 + ((1 - 0.23) *0.23/200}

= 0.02 ± 1.96 * 0.042

= 0.02 + 0.082 = <u>0.102</u>

= 0.02 - 0.082 = <u>-0.062</u>

<u>There is 95% confidence that there is a difference that lies between  - 0.062 and 0.102 on the proportion of students who continued their education in the years, 2017 and 2018.</u>

<u></u>

<u>There is no significant difference between the two.</u>

5 0
3 years ago
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