Answer:
The probability of Yarborough when you are randomly dealt 13 cards out of a well-shuffled deck of 52 card is 0.000547.
Step-by-step explanation:
The number of ways you can choose a set of 13 different cards from a deck of 52 cards is given by 52P13.
Hence the unordered sample space has 52P13 equally likely outcomes. The number of outcomes with no card above a nine is 32P13.
This leads to the same value for the desired probability of a Yarborough:
32P13 / 52P13 = 0.000547.
First what you would have to do is distribute the reciprocal to the (d/3 + 2) and the d/3 is canceled out. You are left with h=6/d. When you put the h over 1 in a fraction, it stays the same. Like in trig, you switch the d and the h and you have d/1=6/h.
d=6/h
Answer:99/14
Step-by-step explanation:
33/7÷4/6
33/7×6/4
(33×6)÷(7×4)
198/28
Reduce to lowest term
99/14
Answer:
100 / 20 = 5
5 * 7 = 35
So the dog ate 35% of it
Step-by-step explanation:
yea so your welcome. im 7 btw
Let the numbers be x and y
y=5x
y-x=236
5x-x=236
4x=236
x=59
5=5*59=295