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Leto [7]
3 years ago
12

Why do we use anticides​

Chemistry
2 answers:
Grace [21]3 years ago
7 0

Answer:

If you mean antacids (bases) it to neutralise stomach acids that have been disturbed.

Explanation:

UkoKoshka [18]3 years ago
4 0
Antacids neutralise the acid made by your stomach. They are commonly used in conditions where it is helpful to neutralise the acid made in the stomach. For example, for acid reflux which causes heartburn. Most people who take antacids do not develop any side-effects.
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Water is a solute. solvent.
Finger [1]

Answer:

solvent

Explanation:

3 0
3 years ago
How do you pass sience
MariettaO [177]

Answer:

Listen in Class. The first step to passing any test is to begin preparing right there in the classroom. ...

Review Lab and Lecture Notes. ...

Know the Vocabulary. ...

Develop a Study Schedule. ...

Take Advantage of Online Study Resources.

Explanation:

8 0
3 years ago
Please answer, with explanation. Thanks!​
nadya68 [22]

Answer:

Explanation:

a = 40.1 g of Ca

Number of moles = mass / molar mass

Number of moles = 40.1 g/ 40.1 g/mol

Number of moles = 1 mol

b = 11.5 g Na

Number of moles = mass / molar mass

Number of moles = 11.5 g/ 23 g/mol

Number of moles = 0.5 mol

c = 5.87 g Ni

Number of moles = mass / molar mass

Number of moles = 5.87 g/ 58.7 g/mol

Number of moles = 0.1 mol

d = 150 g of S

Number of moles = mass / molar mass

Number of moles = 150 g/ 32 g/mol

Number of moles = 4.7 mol

e = 2.65 g Fe

Number of moles = mass / molar mass

Number of moles = 2.65 g/ 55.85 g/mol

Number of moles = 0.05 mol

f = 0.00750 g Ag

Number of moles = mass / molar mass

Number of moles = 0.00750 g/ 107.9 g/mol

Number of moles = 6.95 × 10⁻⁵ mol

g = 2.25 × 10²⁵ atoms Zn

1 mole = 6.022 × 10²³ atoms

1 mol / 6.022 × 10²³ atoms × 2.25 × 10²⁵ atoms

0.17  × 2.25 × 10²⁵ moles

38.25 moles

h = 50 atoms of Ba

1 mole = 6.022 × 10²³ atoms

1 mol / 6.022 × 10²³ atoms ×50 atoms

0.17 × 10²³ × 50 moles

8.5 × 10²³ moles

6 0
3 years ago
Based on the standard free energies of formation, which of the following reactions represent a feasible way to synthesize the pr
yuradex [85]

Explanation:

According the equation of Gibb's free energy -

∆G = ∆H -T∆S

∆G = is the change in gibb's free energy

∆H = is the change in enthalpy

T = temperature

∆S = is the change in entropy .

And , the sign of the  ΔG , determines whether the reaction is Spontaneous or non Spontaneous or at equilibrium ,

i.e. ,

if

• ΔG < 0 , the reaction is Spontaneous

• ΔG > 0 , the reaction is non Spontaneous

• ΔG = 0 , the reaction is at equilibrium

a.

N₂(g) + H₂(g)  → N₂H₄ (g)   ; ΔG⁰f = 159.3 kJ/mol

ΔG > 0 , the reaction is non Spontaneous  , the reaction is not feasible in the forward direction

b.

2Na(s) + O₂(g) → Na₂O₂ (s)   ; ΔG⁰ f = − 447.7kJ/mol

ΔG < 0 , the reaction is Spontaneous  , the reaction is feasible in the forward direction .

c.

C(s) + 2S(s)  →  CS₂ (g)   ; ΔG⁰f = 67.1 kJ/mol

ΔG > 0 , the reaction is non Spontaneous  , the reaction is not feasible in the forward direction

d.

Ca(s) + 12 O₂ (g) → CaO (s) ;  ΔG⁰f = −604.0 kJ/mol

ΔG < 0 , the reaction is Spontaneous  , the reaction is feasible in the forward direction .

8 0
4 years ago
An atom
Natasha2012 [34]

Answer:

Doesnt take up space

Explanation:

Looked it up lol

3 0
4 years ago
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