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White raven [17]
4 years ago
9

What is a joule?

Chemistry
1 answer:
Salsk061 [2.6K]4 years ago
3 0

Answer:

C. A unit of measurement for energy

Explanation:

Joule is the SI unit of

  • Energy
  • Work
  • And Heat

Unit of measurement of mass: Kilogram(Kg)

Unit of measurement of Power: Watt(W)

Unit of measurement of Gravity: m/s^2

Hope this helps ;) ❤❤❤

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The wavelength of the blue light given off by a mercury vapor street lamp is 457 nm. What is the frequency of this light in hert
Fed [463]

Answer:

6.56×10¹⁴ Hz

Explanation:

From the question given above, the following data were obtained:

Wavelength = 457 nm

Frequency =?

Next, we shall convert 457 nm to metre (m). This can be obtained as follow:

1 nm = 1×10¯⁹ m

Therefore,

457 nm = 457 nm × 1×10¯⁹ m / 1 nm

457 nm = 4.57×10¯⁷ m

Thus, 457 nm is equivalent to 4.57×10¯⁷ m

Finally, we shall determine the frequency of the blue light as follow:

Wavelength = 4.57×10¯⁷ m

Velocity of light = 3×10⁸ m/s

Frequency =?

Velocity = wavelength x frequency

3×10⁸ = 4.57×10¯⁷ × frequency

Divide both side by 4.57×10¯⁷

frequency = 3×10⁸ / 4.57×10¯⁷

frequency = 6.56×10¹⁴ Hz

Therefore, the frequency of the blue light is 6.56×10¹⁴ Hz

6 0
3 years ago
Which statement is true about energy changes?
Sindrei [870]

Answer:

D

Explanation:

energy can not be created or destroyed it can only be transferred or changed to one form to another.

7 0
4 years ago
A Gold ring is a what?<br> Element<br> Compound<br> Colloid<br> Alloy
Korvikt [17]

Answer: Alloy

Explanation: gold is an alloy, or mixture of metals

4 0
3 years ago
Which one of the following sets of units is appropriate for a second-order rate constant?
Natalija [7]

Answer:

C. L mol-1 s-1.

Explanation:

Hello,

In this case, a rate law has the following general form:

r=kC^x_i

Whereas r accounts for the rate measured in M/s units, k is the rate constant whose units depends on the order of the reaction, C the concentration of the species in M units, contributing to the rate and x the order of the reaction.

In such a way, since in this case x equals two (second-order rate), the units of k turns out:

\frac{M}{s}=\frac{mol}{L*s}=k*(\frac{mol}{L}) ^2\\\frac{mol}{L*s}=k*\frac{mol^2}{L^2}\\\\k=\frac{L^2*mol}{mol^2*L*s} \\\\k=\frac{L}{mol*s}

Which matches with C. L mol-1 s-1.

Best regards.

5 0
3 years ago
Where would you find the asthenosphere?
Harman [31]

Answer:

b. upper mantle

Explanation:

low velocity zone of the upper mantle

3 0
3 years ago
Read 2 more answers
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