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borishaifa [10]
3 years ago
12

Can a triangle be formed with the sides lengths of 9 cm, 2 cm and 11 cm

Mathematics
2 answers:
mariarad [96]3 years ago
8 0

Answer:

yessssss

Step-by-step explanation:

scoray [572]3 years ago
3 0

Answer:no it can not

Step-by-step explanation:

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Express the following expression in the form of a + bi: (39 + 34i) + (76 + 89i) - (47 +26i).
andre [41]

Answer:

68+97i

Step-by-step explanation:

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3 0
3 years ago
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What time and day will it be <br> 154hr 36 mins after Thursday 1:26pm?
loris [4]

Answer:

12:02 AM on the next Thursday

Step-by-step explanation:

First we wanna find how many days that is.  154/24.  that is 6 and 5/12 days.

5/12 of a day is equal to 10/24, so 10 hours, sice there are 24 hours in a day.

so that's 10 hours and 36 minutes which equals 2:02 pm + 10 hours 12:02 AM on Friday

Now just add the 6 days so 12:02 AM on the next Thursday

5 0
3 years ago
after an art class 15% of the color pencils were missing. how many color pencils were there originally if 9 color pencils are no
NARA [144]
We know that the 15% of missing pencils is equal to 9

we can use this formula

9/x = 15/100

Then cross multiply

15x = 900

x = 60

There were orignally 60 pencils
8 0
3 years ago
What is the volume of this cylinder?
Leviafan [203]
V cylinder = pi * r^2 * h
V = 3.14 * 5^2 * 8
V = 3.14 * 25 * 8
V = 628 ft^3
6 0
3 years ago
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A population of insects grows exponentially, as shown in the table. Suppose the increase in population continues at the same rat
Ivanshal [37]

We are told that a population of insects grows exponentially and we are given a table of data about insect population growth. We are asked to find population of insects at the end of week 11.        

The initial insect population is 20 and at the end of 1st week population increases to 30.

Let us find growth percentage of insect  population,

\text{Growth percentage}=\frac{\text{Difference}}{Actual} \cdot100

\text{Growth percentage}=\frac{\text{30-20}}{20} \cdot100

\text{Growth percentage}=\frac{\text{10}}{20} \cdot100

\text{Growth percentage}=0.5 \cdot100=50

We can see that insect population is growing at rate of 50% per week.

Now let us write an exponential function for our population.

P(w)=20(1+0.50)^{w}, where P(w) represents population at the end of w weeks.

Let us substitute w=11 in our function to find insect population at the end of 11 weeks.

P(11)=20(1+0.50)^{11}

P(11)=20(1.50)^{11}

P(11)=20\cdot 86.49755859375

P(11)=1729.951171875\approx 1730

Therefore, population of insects at the end of 11th week will be 1730.  



7 0
3 years ago
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