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jeka57 [31]
3 years ago
7

joyce traveled at an average speed of 60 miles per hour for 4.5 hours and then traveled at an average speed of 35 miles per hour

for 1.5 hours. What was the total distance in miles that joyce traveled during this time ?
Mathematics
1 answer:
SVEN [57.7K]3 years ago
8 0

Answer:

322 1/2 miles

Step-by-step explanation:

Recall how s = d/t ; speed = distance/time.

To effectively solve for distance traveled, rearrange the formula so that distance is on the left-hand side by multiplying speed, and time.

speed × time = distance/time × time

speed × time = distance

distance = speed × time ; d = st.

Now to find the total distance traveled, individually multiply the rate of speed with the time. Time will cancel, and we will get the total mileage.

Given an average speed of 60 mph at a certain time for 4.5 hours, and another average speed of 35 mph at another time of 1.5. Calculate the distance individually, and then add both distances together. Distance 1 = 60 mph × 4.5 h = 60 miles / h × 4.5h = 60 miles × 4.5 = 270 miles.

Distance 2 = 35mph × 1.5h = 35 miles / h × 1.5h = 35 miles × 1.5 = 52 1/2 miles.

Distance 1 + Distance 2 = Total distance.

270 miles + 52 1/2 miles = 322 1/2 miles.

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\fbox{ \fbox { \sf{Distance  =  \sf{15 \: units}}}}

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Best regards! :D

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