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trapecia [35]
3 years ago
7

what’s the total area of a converter box buildings of 4 feet, width of 3 feet,and a height of 6 feet?

Mathematics
1 answer:
Katena32 [7]3 years ago
7 0
The total will be 72
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Help I mark brainliest
Serga [27]

Answer:

-\frac{1}{5} t^{15}

Step-by-step explanation:

sry if im wrong

3 0
3 years ago
According to the census data, in 2014 about 126 million adults in the United States were women, which is about 51.4% of the tota
jeka57 [31]

Answer:

245.1361868

Step-by-step explanation:

126               51.4

___    =        ____             126x100=12600      12600/51.4=245.1361868

 x                  100

6 0
3 years ago
If u answer this I'll make a random question with a 100 points on it so u can get it
mario62 [17]

Answer:

5 and a half hours

Brainliest maybe?

3 0
2 years ago
Read 2 more answers
An equilateral ∆ has sides of length 16 cm. Find the length of an altitude.
inn [45]

The length of the altitude is 8\sqrt{3}

Explanation:

Let ABC be an equilateral triangle.

It has sides of length 16 cm

Let AD be the altitude of the triangle.

We need to determine the length of an altitude.

Let AC = 16 cm and CD = 8 cm

Let us consider the right angled triangle ADC

Using the Pythagorean theorem, we have,

AC^2=AD^2+DC^2

Substituting the values, we get,

 16^2=AD^2+8^2

 256=AD^2+64

 192=AD^2

8\sqrt{3}=AD

The length of the altitude is 8\sqrt{3}

5 0
3 years ago
1. Write the equation of the piece-wise function graphed below​.
DaniilM [7]

Problem 4

<h3>Answer:</h3>

f(x) = \begin{cases}2x+4 \text{ if } x < 1\\x-3 \text{ if } x \ge 1\end{cases}

------------------

Work Shown:

The left line goes through (-2,0) and (0,4)

The slope of this line is

m = (y2-y1)/(x2-x1)

m = (4-0)/(0-(-2))

m = (4-0)/(0+2)

m = 4/2

m = 2

The y intercept is b = 4

Since m = 2 and b = 4, this means y = mx+b turns into y = 2x+4. This portion is only done when x < 1. Note the open circle at the endpoint of this portion. So we do not include x = 1 as part of this piece.

---

The line on the right side goes through (1,-2) and (2,-1)

Slope

m = (y2-y1)/(x2-x1)

m = (-1-(-2))/(2-1)

m = (-1+2)/(2-1)

m = 1/1

m = 1

The y intercept is b = -3. You can see this if you extend the line until it crosses the y axis.

Alternatively, plug in (x,y) = (1,-2) and m = 1 into y = mx+b to find that b = -3

So y = mx+b turns into y = 1x+(-3) or just y = x-3

We combine both parts to end up with f(x) = \begin{cases}2x+4 \text{ if } x < 1\\x-3 \text{ if } x \ge 1\end{cases}

This is only graphed when x \ge 1 (note the closed or filled in circle for the endpoint of this portion).

===================================================

Problem 5

Answer:

<h3>f(x) = \frac{1}{2}|x+3| is the absolute value function</h3><h3>while this is the piecewise function</h3>

f(x) = \begin{cases}-\frac{1}{2}(x+3) \text{ if } x < -3\\\frac{1}{2}(x+3) \text{ if } x \ge -3\end{cases}\\

------------------

Work Shown:

y = |x| .... parent function

y = |x+3| ... shift 3 units to the left

y = (1/2)*|x+3| .... vertically compress by factor of 1/2

f(x) = (1/2)*|x+3|

------

Break that down into a piecewise function

when x < -3, then y = -(1/2)(x+3)

when x \ge -3, then y = (1/2)(x+3)

I'm using the rule that y = |x| turns into y = -x when x < 0 and y = x when x \ge 0

So that is how we get f(x) = \begin{cases}-\frac{1}{2}(x+3) \text{ if } x < -3\\\frac{1}{2}(x+3) \text{ if } x \ge -3\end{cases}\\as the piecewise function.

8 0
3 years ago
Read 2 more answers
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