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trapecia [35]
3 years ago
7

what’s the total area of a converter box buildings of 4 feet, width of 3 feet,and a height of 6 feet?

Mathematics
1 answer:
Katena32 [7]3 years ago
7 0
The total will be 72
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Calculate the following limit:
aleksklad [387]
\lim_{x\to\infty}\dfrac{\sqrt x}{\sqrt{x+\sqrt{x+\sqrt x}}}=\\
\lim_{x\to\infty}\dfrac{\dfrac{\sqrt x}{\sqrt x}}{\dfrac{\sqrt{x+\sqrt{x+\sqrt x}}}{\sqrt x}}=\\
\lim_{x\to\infty}\dfrac{1}{\sqrt{\dfrac{x+\sqrt{x+\sqrt x}}{x}}}=\\
\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\dfrac{\sqrt{x+\sqrt x}}{x}}}=\\
\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\dfrac{\sqrt{x+\sqrt x}}{\sqrt{x^2}}}}=\\
\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\sqrt{\dfrac{x+\sqrt x}{x^2}}}}=\\\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\sqrt{\dfrac{1}{x}+\dfrac{\sqrt x}{\sqrt{x^4}}}}}=\\\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\sqrt{\dfrac{1}{x}+\sqrt{\dfrac{x}{x^4}}}}}=\\
\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\sqrt{\dfrac{1}{x}+\sqrt{\dfrac{1}{x^3}}}}}=\\
=\dfrac{1}{\sqrt{1+\sqrt{0+\sqrt{0}}}}=\\
=\dfrac{1}{\sqrt{1+0}}=\\
=\dfrac{1}{\sqrt{1}}=\\
=\dfrac{1}{1}=\\
1


8 0
2 years ago
40 POINTS PLEASE HELPPPPPPP ME !
IrinaK [193]

Answer:

75/100

=15/20

3/4

The probability is3/4

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Rachel has a box in the shape of a prism with a square base. The capacity of the box is 150 cubic inches. The height of the box
hjlf
V = s²h 

<span>150 = s²h </span>
<span>150 = s²(3/2)s </span>
<span>(2/3)150 = s³ </span>
<span>100 = s³ </span>
<span>s = ∛100 (approx 4.642 in) </span>
6 0
3 years ago
I need a-e to be solved I’m confused still
monitta
A) 36 means that there are 36 students taking Italian and music AT SAME TIME

b) 59 means that there are 59 students taking only music 

c) 48 means that there are 48 students taking neither Italian nor music

d) Italian OR Music = 97 + 36 +59 = 192

e) Do not take Italian: 48 + 59 = 107

7 0
3 years ago
PLS HELPP MEE The question is in the picture below
kotegsom [21]
Im pretty sure it would be $60. If im wrong im sorryyyyy
8 0
3 years ago
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