Question

Calculate the buoyant force due to the surrounding air on a man weighing 600 N . Assume his average density is the same as that of water. Suppose that the density of air is 1.20 kg/m3.

Answer 1

Answer:

$F_b= 0.720 N$

Explanation:

From the question we are told that:

Weight $W=600N$

Average density $\rho=1.20kg/m^3$

Mass

$m=\frac{W}{g}$

$m=\frac{600}{9.81}$

$m=61.22kg$

Generally the equation for Volume is mathematically given by

$V =\frac{ mass}{density}$

$V= \frac{61.22}{1000}$

$V=0.06122 m^3$

Therefore

Buoyant force $F_b$

$F_b=\rho*V*g$

$F_b= rho_air*V*g$

$F_b= 0.720 N$