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3 years ago

Which was a testable idea that J.J. Thomson developed through his experiments

Physics

2 answers:

Natalka [10]3 years ago

6 0

Cathode ray tube, plumb pudding model, atoms were not hard spheres, but had smaller parts.

stich3 [128]3 years ago

4 0

atoms contained small, negatively charged particles

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Two identical conducting small spheres are placed with their centers 0.290 m apart. One is given a charge of 12.0 nC and the oth

Solnce55 [7]

Answer:

Force between two identical conducting ball will be $2.65\times 10^{-5}N$

Explanation:

We have given there is two identical conducting small spheres having charge $q_1=12nC=12\times 10^{-9}C$ and $q_2=-21nC=-21\times 10^{-9}C$

Distance between centers of the ball is 0.290 m

So r = 0.290 m

We have to fond the electric force between the balls

According to Coulomb's law force between two charges is given by

$F=\frac{1}{4\pi \epsilon _0}\frac{q_1_2}{r^2}=\frac{Kq_1q_2}{r^2}$

So force $F=\frac{9\times 10^{9}\times 12\times 10^{-9}\times 21\times 10^{-9}}{0.293^2}=2.65\times 10^{-5}N$

So force between two identical conducting ball will be $2.65\times 10^{-5}N$

4 0

3 years ago

In a series circuit what effect will adding more resistors to the circuit have

zhuklara [117]

Answer:In a series circuit, adding more resistors increases total resistance and thus lowers current. But the opposite is true in a parallel circuit because adding more resistors in parallel creates more choices and lowers total resistance. If the same battery is connected to the resistors, current will increase.

Explanation:

8 0

3 years ago

A motorcycle is travelling at a constant velocity of 90 km/h (no acceleration). How many

Mazyrski [523]

2km*1000=2000m
S=ut+1/2at^2
a=0,thus s=ut
2000=90t
t=2000/90
=22.22s(to 4 s.f)
Please mark as brainliest

8 0

3 years ago

How do you use physics?

Firlakuza [10]

Answer:

Physics extends well into your everyday life, describing the motion, forces and energy of ordinary experience. In actions such as walking, driving a car or using a phone, physics is at work. For everyday living, all the technologies you might take for granted exploit the rules of physics.

Explanation:

3 0

3 years ago

Read 2 more answers

Two 2.0-cm-diameter insulating spheres have a 6.60 cm space between them. One sphere is charged to + 76.0 nC , the other to - 30

e-lub [12.9K]

Answer:

$5.2\times 10^5N/C$

Explanation:

Since the two charged bodies are symmetric, we can calculate the electric field taking both of them as point charges.

This can be easily seen if we use Gauss's law, $\int{E} \, dA=\frac{Q_{enclosed}}{\epsilon_o}$

We take a larger sphere of radius, say r, as the Gaussian surface. Then the electric field due to the charged sphere at a distance r from it's center is given by,

$E=\frac{1}{4\pi r^2} \frac{Q_{enclosed}}{\epsilon_o}$

which is the same as that of a point charge.

In our problem the charges being of opposite signs, the electric field will add up. Therefore,

$E_{total}=\frac{1}{4\pi\epsilon_o}\frac{q_1+q_2}{r^2}= (9\times10^9) \frac{(76+30)\times10^{-9}}{((1+3.3)\times10^{-2})^2}N/C =5.2\times10^5N/C$

where, $r$ = distance between the center of one sphere to the midpoint (between the 2 spheres)

8 0

3 years ago