Answer:
Length of a tube = 1.574 m
Explanation:
Given:
Fundamental frequency (f1) = 108 Hz
First overtone (f2) = 216 Hz
Speed of sound (v) = 340 m/s
Find:
Length of a tube
Computation:
We know that,
f = v / λ
f = nv / 2L [n = number 1,2,3]
So,
f1 = 1(340) / 2L
f1 = 170 / L
L = 170 / 108 = 1.574 m
f2 = 2(340) / 2L
L = 340 / 216
L = 1.574 m
Answer:
2200000 = 2.2E6 min for light from Proxima to reach earth
8.3 min from light sun to reach earth
2.2E6/8.3 = 2.56E5 times for light from Proxima
Proxima is about 256,000 times farther away than the sun
Since the sun is about 93,000,000 = 9.3E7 miles from earth
Proxima is then 9.3E7 * 2.56E5 = 2.4E13 miles away
Note - the speed of light is
3.00E8 m/s * 60 s/min / 1000 m/km = 1.8E7 km/min as given
Answer:
The sprinter need to climb 6.17 m
Explanation:
From the question,
Ep = Ek...................... Equation 1
Where Ep = potential energy, Ek = kinetic energy.
therefore,
mgh = 1/2mv².................... Equation 2
Where m = mass of the human, v = speed, h = height, g = acceleration due to gravity.
making h the subject of formula in equation 2
h = 1/2v²/g...................... Equation 3
Given: v = 11 m/s
Constant: g = 9.8 m/s²
Substituting these values into equation 3,
h = 1/2(11²)/9.8
h = 6.17 m.
Therefore the sprinter need to climb 6.17 m
It might be force but i don’t remember
