How coal power plants produce electrical energy to power our homes

The speed of sound at room temperature (20 degrees Celsius) is 343 m/s. If the speed of sound in air increases about 0.60 m/s fo

stepan [7]

Answer:

36,67 degrees Celsius

Explanation:

The simplest way to approach this problem, given the information provided, is to simply start with the speed difference.

Goal: 353 m/s

Start: 343 m/s (at 20 degrees Celsius).

Difference: 10 m/s

Variation rate: 0.60 m/s/d (d = degree)

$d = \frac{10 m/s}{0.60 m/s/d} = 16,67 d$

So, 16,67 degrees more than the starting point.

The temperature will then be 36.67 degrees Celsius, when the sound travels at the speed of 353 m/s.

4 0

3 years ago

Write the total equation for the proton-proton chain reaction that takes place in stars?

Sav [38]

Supernova?? lollll.

6 0

2 years ago

2) [25 pts] The bob of mass m=5 kg shown in the figure is being held by a force F. If the angle is 0⃗

Colt1911 [192]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

The tension is $T = 48.255 \ N$

b

The time taken is $t = 0.226 \ s$

c

The position for maximum velocity is

S = 0

d

The maximum velocity is $V_{max} =0.384 \ m/s$

Explanation:

The free body for this question is shown on the second uploaded image

From the question we are told that

The mass of the bob is $m_b = 5 \ kg$

The angle is $\theta = 10^o$

The length of the string is $L = 0.5 \ m$

The tension on the string is mathematically represented as

$T = mg cos \theta$

substituting values

$T = 5 * 9.8 cos(10)$

$T = 48.255 \ N$

The motion of the bob is mathematically represented as

$S = A sin (w t + \frac{\pi }{2} )$

=> $S = A sin (wt)$

Where $w$ is the angular speed

and $\frac{\pi}{2}$ is the phase change

At initial position S = 0

So $wt = cos^{-1} (0)$

$wt = 1$

Generally $w$ can be mathematically represented as

$w = \frac{2 \pi }{T}$

Where T is the period of oscillation which i mathematically represented as

$T = 2 \pi \sqrt{\frac{L}{g} }$

So

$t = \frac{1}{w}$

$t = \frac{T}{2 \pi}$

$t = \sqrt{\frac{L}{g} }$

substituting values

$t = \sqrt{\frac{0.5}{9.8} }$

$t = 0.226 \ s$

Looking at the equation

$wt = 1$

We see that maximum velocity of the bob will be at S = 0

i. e $w = \frac{1}{t}$

The maximum velocity is mathematically represented as

$V_{max} = w A$

Where A is the amplitude which is mathematically represented as

$A = L sin \theta$

So

$V_{max} = \frac{2 \pi }{T } L sin \theta$

$V_{max} = \frac{2 \pi }{2 \pi } \sqrt{\frac{g}{L} } L sin \theta$ Recall $T = 2 \pi \sqrt{\frac{L}{g} }$

$V_{max} = \sqrt{gL} sin \theta$

substituting values

$V_{max} = \sqrt{9.8 * 0.5 } sin (10)$

$V_{max} =0.384 \ m/s$

6 0

2 years ago

What is the approximate terminal velocity of a sky diver before the parachute opens

anzhelika [568]

Answer:

The approximate terminal velocity of a sky diver before the parachute opens is 320 km/h.

Explanation:

The terminal velocity is the maximum magnitude of velocity that is attained by the diver when he or she falls in the air.
The terminal velocity of the person diving in air before opening parachute is 320 km/h that means the velocity when the person is experiencing free fall is 320 km/h.
During terminal velocity, we can represent mathematical equation as;

Buoyancy force + drag force = Gravity

6 0

3 years ago

All but two gaps within a set of Venetian blinds have been blocked off to create a double-slit system. These gaps are separated

Alecsey [184]

Answer:

Explanation:

separation between two gaps, d = 5 cm

angle between central and second order maxima, θ = 0.52°

use

d Sinθ = n λ

n = 2

0.05 x Sin 0.52° = 2 x λ

λ = 2.27 x 10^-4 m

λ = 226.9 micro metre

6 0

3 years ago