Answer and Step-by-step explanation:
Although the question is not complete, but with the context of the question, they are most likely going to ask for the total distance travelled or the total time or speed. So let's work on that.
Total time travelled = (3 + 5 + 4) = 12mins
Total speed travelled = (0.50 + 0.00 + 0.40)miles/min = 0.90mile/min
The 0.00 represents the period he was at rest admiring an antique car. At this moment, he was not moving so his speed is 0.
Total distance travelled = total speed x total time = 0.90miles/min x 12min = 10.8miles
The table isn’t shown so I cant tell
Complete question :
Birth Month Frequency
January-March 67
April-June 56
July-September 30
October-December 37
Answer:
Yes, There is significant evidence to conclude that hockey players' birthdates are not uniformly distributed throughout the year.
Step-by-step explanation:
Observed value, O
Mean value, E
The test statistic :
χ² = (O - E)² / E
E = Σx / n = (67+56+30+37)/4 = 47.5
χ² = ((67-47.5)^2 /47.5) + ((56-47.5)^2 /47.5) + ((30-47.5)^2/47.5) + ((37-47.5)^2/47.5) = 18.295
Degree of freedom = (Number of categories - 1) = 4 - 1 = 3
Using the Pvalue from Chisquare calculator :
χ² (18.295 ; df = 3) = 0.00038
Since the obtained Pvalue is so small ;
P < α ; We reject H0 and conclude that there is significant evidence to suggest that hockey players' birthdates are not uniformly distributed throughout the year.
Answer:
The answer is 
.
Step-by-step explanation:
First, it is important to recall that the group law is not commutative in general, so we cannot assume it here. In order to solve the exercise we need to remember the axioms of group, specially the existence of the inverse element, i.e., for each element 
there exist another element, denoted by 
such that 
, where 
stands for the identity element of G.
So, given the equality 
we make a left multiplication by 
and we obtain:
But, 
. Hence, 
.
Now, in the equality we make a right multiplication by 
, and we obtain
.
Recall that 
and 
. Therefore,
.
