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3 years ago

I have no clue what I’m doing can someone help me with number 5

Mathematics

1 answer:

marin [14]3 years ago

5 0

a) 35w+55-10w = 25w+55

28w+75-5w+12 = 23w +87

b) 25w+55 + 23w +87

=48w+142

they will be short by 2(24w+71)

c) 50w+25 = 25(2w+1)

answer: =98w+167

i think

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I need help with both of these someone please help me . you’ll get 20 brainly points !!

Orlov [11]

Answer:

First question: 42cm^2

Second question:

whole figure: 150 cm^2

blue part: 96cm^2

white part:54cm^2

Step-by-step explanation:

Lets do math:

look you gave me alot to do but lets go:

Question 1:

lets find the area of the whole rectangle without the parts taken away.

6*10-60

lets put that away for a little bit and move onto the empty space that we have to take away from the rectangle to get this shape.

im now going to subtract 2 from 10 to get 8. I did this to find out the a length

8*3=24

18 is the area of the shape that we have to subtract from the big rectangle

lets now take out the area we put away for a little while.

60-18=42

so 42 is the area of the first shape.

Question #2:

This problem needs multiple answers so lets get started.

first we need to find the area of the big rectangle.

10*15=150

lets put that away for a little bit.

now lets find the area of the little rectangle

6*9=54

to find the blue we have to subtract 54 from 150 which is 96

so now we have this:

area of the whole figure:150

area of the shaded rectangle inside (white): 54

area of the shaded rectangle (blue): 96

phew that was a lot of typing

the end

8 0

3 years ago

Maci and I are making a small kite. Two sides are 10". Two sides are 5". The shorter diagonal is 6". Round all your answers to t

Art [367]

Answer:

A. 4".

B. Approximately 9.54".

C. Approximately 13.54".

Step-by-step explanation:

Please find the attachment.

Let x be the distance from the peak of the kite to the intersection of the diagonals and y be the distance from the peak of the kite to the intersection of the diagonals.

We have been given that two sides of a kite are 10 inches and two sides are 5 inches. The shorter diagonal is 6 inches.

A. Since we know that the diagonals of a kite are perpendicular and one diagonal (the main diagonal) is the perpendicular bisector of the shorter diagonal.

We can see from our attachment that point O is the intersection of both diagonals. In triangle AOD the side length AD will be hypotenuse and side length DO will be one leg.

We can find the value of x using Pythagorean theorem as:

$(AO)^2=(AD)^2-(DO)^2$

$x^{2}=5^2-3^2$

$x^{2}=25-9$

$x^{2}=16$

Upon taking square root of both sides of our equation we will get,

$x=\sqrt{16}$

$x=\pm 4$

Since distance can not be negative, therefore, the distance from the peak of the kite to the intersection of the diagonals is 4 inches.

B. We can see from our attachment that point O is the intersection of both diagonals. In triangle DOC the side length DC will be hypotenuse and side length DO will be one leg.

We can find the value of y using Pythagorean theorem as:

$(OC)^2=(DC)^2-(DO)^2$

Upon substituting our given values we will get,

$y^2=10^2-3^2$

$y^2=100-9$

$y^2=91$

Upon taking square root of both sides of our equation we will get,

$y=\sqrt{91}$

$y\pm 9.539392$

$y\pm\approx 9.54$

Since distance can not be negative, therefore, the distance from intersection of the diagonals to the top of the tail is approximately 9.54 inches.

C. We can see from our diagram that the length of longer diagram will be the sum of x and y.

$\text{The length of the longer diagonal}=x+y$