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3 years ago

Point A is located at and point B is located at . What is the distance between points A and B? (1 point)

2 answers:

4 0

As your question is missing some information, so after some research I was able to find the potential question you wanted to ask which is:

Point A is located at negative 4 over 6 and point B is located at negative 1 over 6. What is the distance between points A and B?

So, I am going to answer you based on the complete question I was able to find, which anyways would clear your concept.

Answer:

The distance between A and B will be: $\frac{3}{6}$

Step-by-step explanation:

From the question statement, it is clear that

Point A is located at negative 4 over 6 i.e. -4/6, and

point B is located at negative 1 over 6 i.e. -1/6.

As we know that we can determine the distance between two negative numbers on a given line by finding the distance by taking the absolute value of the difference between those numbers.

so,

Distance between A and B will be:

$\left|-\frac{4}{6}-\left(-\frac{1}{6}\right)\right|=\left|-\frac{4}{6}+\frac{1}{6}\right|$

$=\left|\frac{-4+1}{6}\right|$

$=\left|-\frac{3}{6}\right|$

$=\frac{3}{6}$

Hence, the distance between A and B will be: $\frac{3}{6}$

Leni [432]3 years ago

3 0

point A is located at -2, 5

point B is located at 5,5

the distance is 7 units

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Wittaler [7]

Step-by-step explanation:

If you need help with how I got my answer, you can ask me.

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$( \frac{2u {}^{ 4} }{ - u {}^{2}v {}^{ - 1} \times 2uv {}^{ - 4} } ) {}^{ - 1}$

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$( - u v {}^{ 5} ) {}^{ - 1}$

$= - u {}^{ - 1} v {}^{ - 5} = - \frac{ 1}{uv {}^{5} }$

13.

$- \frac{2m {}^{4}n {}^{ - 1} }{( - m {}^{2}n {}^{ - 2}) {}^{ - 1} \times - nm {}^{ - 3} }$

$- \frac{2m {}^{4}n {}^{ - 1} }{ - m {}^{ - 2} n {}^{2} \times - nm {}^{ - 3} }$

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$= - \frac{2m {}^{9} }{n {}^{4} }$

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$( \frac{x {}^{3}y {}^{ - 4} }{ - {x}^{2} y {}^{ - 3} \times yx {}^{0} } ) {}^{3}$

$( \frac{x {}^{3}y {}^{ - 4} }{ - {x}^{ - 2}y {}^{ - 2} } ) {}^{3}$

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$- \frac{yx {}^{4} \times - {y}^{3} z { }^{ - 4} }{(z {y}^{2} ) {}^{4} }$

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$\frac{h {}^{7}j {k}^{4} }{4h {}^{4} } = \frac{1}{4} h {}^{3} = \frac{h {}^{3} jk {}^{4} }{4}$

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3 years ago

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Alexus [3.1K]

Answer:

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Step-by-step explanation:

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3 years ago

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sasho [114]

Answer:

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Step-by-step explanation:

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6 0

3 years ago

Read 2 more answers

60 books represent 1 percent of the total books in the library 3

ICE Princess25 [194]

Answer:

180

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If this is not what u r looking for please rephrase ur question

8 0

3 years ago

Evaluate: <img src="https://tex.z-dn.net/?f=%5Csqrt%5B-3%5D%7B27%7D" id="TexFormula1" title="\sqrt[-3]{27}" alt="\sqrt[-3]{27}"

GenaCL600 [577]

Answer:

1/3 is the simplified form for given expression.

Step-by-step explanation:

Given that:

= $\sqrt[-3]{27}$

By simplifying:

Radical sign will be removed as follows:

= $27^{-1/3}$

For removing the "-" sign from power, base will be inverted:

= $(1/27) ^ {1/3}$

27 can also be written as 3 * 3 * 3 = 3^3

So,

= $(1/3^3)^{1/3}$

= $1^{1/3} / 3^{3* 1/3}$

By simplifying we get:

= 1/3

i hope it will help you!

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3 years ago