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2 years ago

(8√2 - 5) (9√5 +6√10) Simplify

Mathematics

1 answer:

salantis [7]2 years ago

5 0

Answer:

42 (square root>) 10 + 51 (square root>) 5

Step-by-step explanation:

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Is 14/35 and 21/42 proportional

PIT_PIT [208]

1.Simplified each one
2/5 (both divided by 7) , 1/2 (divided by 21)
2.Make them into integer
(2/5 )*(2/2)=4/10 , (1/2)*(5/5)=5/10
Now the dominators are the same ,you can just compare the numerators. It is 4:5

8 0

2 years ago

127 3/4 miles is 35% of what number of miles?

ale4655 [162]

Answer:

It is the 35% percent of 365 miles.

Step-by-step explanation:

Use formula,

35%*x=127 3/4

4 0

2 years ago

How do you find the inverse of a function on a graph

Yanka [14]

Answer:

visual wise: you mirror it

Step-by-step explanation:

7 0

2 years ago

The expression (secx + tanx)2 is the same as _____.

trapecia [35]

<u>Answer:</u>

The expression $\bold{(\sec x+\tan x)^{2} \text { is same as } \frac{1+\sin x}{1-\sin x}}$

<u>Solution:</u>

From question, given that $\bold{(\sec x+\tan x)^{2}}$

By using the trigonometric identity $(a + b)^{2} = a^{2} + 2ab + b^{2}$ the above equation becomes,

$(\sec x+\tan x)^{2} = \sec ^{2} x+2 \sec x \tan x+\tan ^{2} x$

We know that $\sec x=\frac{1}{\cos x} ; \tan x=\frac{\sin x}{\cos x}$

$(\sec x+\tan x)^{2}=\frac{1}{\cos ^{2} x}+2 \frac{1}{\cos x} \frac{\sin x}{\cos x}+\frac{\sin ^{2} x}{\cos ^{2} x}$

$=\frac{1}{\cos ^{2} x}+\frac{2 \sin x}{\cos ^{2} x}+\frac{\sin ^{2} x}{\cos ^{2} x}$

On simplication we get

$=\frac{1+2 \sin x+\sin ^{2} x}{\cos ^{2} x}$

By using the trigonometric identity $\cos ^{2} x=1-\sin ^{2} x$ ,the above equation becomes

$=\frac{1+2 \sin x+\sin ^{2} x}{1-\sin ^{2} x}$

By using the trigonometric identity $(a+b)^{2}=a^{2}+2ab+b^{2}$

we get $1+2 \sin x+\sin ^{2} x=(1+\sin x)^{2}$

$=\frac{(1+\sin x)^{2}}{1-\sin ^{2} x}$

$=\frac{(1+\sin x)(1+\sin x)}{1-\sin ^{2} x}$

By using the trigonometric identity $a^{2}-b^{2}=(a+b)(a-b)$ we get $1-\sin ^{2} x=(1+\sin x)(1-\sin x)$

$=\frac{(1+\sin x)(1+\sin x)}{(1+\sin x)(1-\sin x)}$

$= \frac{1+\sin x}{1-\sin x}$

Hence the expression $\bold{(\sec x+\tan x)^{2} \text { is same as } \frac{1+\sin x}{1-\sin x}}$

8 0

2 years ago

If the polygon is translated 2 units down and 4 units left what will the coordinates of the new image be? Use prime notation in

Luda [366]

Answer:

A’ is (3,-3)

B’ is (-1,-4)

C’ is (-1,2)

D’ is (3,1)

Step-by-step explanation: i forgot how i did this but i did it last week in math or somthing sorry if its wrong it was right for me

5 0

2 years ago