All categories

2 years ago

H(v)=5v2–28v+11, use synthetic division to find h(4).

Mathematics

1 answer:

kotykmax [81]2 years ago

4 0

Answer:

h(4)=-21

Step-by-step explanation:

h(v)=5x^2-28v+11

h(4)=5(4)^2-28(4)+11

h(4)=5(16)-112+11

h(4)=80-101

h(4)=-21

If this helps please mark as brainliest

You might be interested in

Will someone check my awnsers on my geometry b exam for me

kogti [31]

Sure but wheres the picture?

3 0

3 years ago

What is the equation of the line that passes through the point (-4,2) and has a slope of 1/4

zubka84 [21]

Step-by-step explanation:

Equation of line is y-y1 = m(x-x1), where m is the slope and (x1,y1) is the given point.

y-2 = 1/4*(x-(-4))

y-2 = 1/4 * (x+4)

4*(y-2) = x+4

Equation of the line is,

x-4y = -12

8 0

2 years ago

Expand the expression 2/7(2s+3)

xxTIMURxx [149]

48/7 + 6/7 if your having any other trouble let me no

8 0

3 years ago

Read 2 more answers

A ladder 16 feet long is leaning against the wall of a tall building. The base of the ladder is moving away from the wall at a r

svet-max [94.6K]

Answer:

a. 0.588

b. 0.0722

c. 4.576 sqft/sec

Step-by-step explanation:

Let b and h denote the base and height as indicated in the diagram. By pythagoras theorem, $h^2 + b^2 = 16^2 = 256 \dotsc\;(1)$ because it is a right angle triangle.

It is given that $\frac{db}{dt} = 1$

Now differentiate (1) with respect to t (time) :

$\displaystyle{2h\frac{dh}{dt} + 2b\frac{db}{dt} = 0 \implies \frac{dh}{dt} = -\frac{b}{h} \frac{db}{dt}}$

$\displaystyle{=-\frac{b}{\sqrt{256 - b^2}} \frac{db}{dt} = -\frac{8}{13.856} \times 1 = -0.588}$

The minus sign indicates that the value of h is actually decreasing. The required answer is 0.588.

b. From the diagram, infer that $16 \sin{\theta} = b$ . When b = 8, then $\theta = \arcsin{0.5} = \ang{30}$ .

Differentiate the above equation w.r.t t

$\displaystyle{16 \cos{\theta} \frac{d\theta}{dt} = \frac{db}{dt} \implies \frac{d\theta}{dt} = \frac{1}{16 \cos{\theta}} = \frac{1}{13.856} = \mathbf{0.0722}}$