HELP ME PLEASE geometry only answer if you know please!
1 answer:
You might be interested in
Answer:
Step-by-step explanation:
Firstly, we know that the solution cannot contain as when x=3, the equation is undefined. This cuts the options in half
When we plug in a value that is less than 3, we always get a value less than 1. This means that when added to 3, we will always get a value less than 4.
Answer:
Mari needs 27 and 39 oranges for 9 and 13 bags respectively.
Step-by-step explanation:
Consider the below figure attached with this question.
From the below table it is clear the she need 9 oranges for 3 bags.
Number of oranges in each bag = 9/3 = 3 oranges
She packs 3 oranges in each bag.
For 9 bags, the number of oranges = 9×3 = 27 oranges.
For 13 bags, the number of oranges = 13×3 = 39 oranges.
Therefore, Mari needs 27 and 39 oranges for 9 and 13 bags respectively.
Answer:
Step-by-step explanation:
Hello!
The variable of interest is the readings on thermometers. This variable is normally distributed with mean μ= 0 degrees C and standard deviation σ= 1.00 degrees C.
The objective is to find the readings that are in the top 3.3% of the distribution and the lowest 3.3% of the distribution.
Symbolically:
The lower value P(X≤a)=0.033
Top value P(X≥b)=0.033
(see attachment)
Lower value:
The accumulated probability until "a" is 0.03, since the variable has a normal distribution, to reach the value of temperature that has the lowest 3.3%, you have to work under the standard normal distribution.
First we look the Z value corresponding to 0.033 of probability:
Z= -1.838
Now you reverste the standardization using the formula Z= (a-μ)/δ
a= (Z*δ)+μ
a= (-1.838*1)+0
a= -1.838
Top value:
P(X≥b)=0.033
This value has 0.033 of the distribution above it then 1 - 0.033= 0.967
is below it.
You can rewrite the expression as:
P(X≤b)=0.967
Now you have to look the value of Z that corresponds to 0.967 of accumulated probability:
b= (Z*δ)+μ
b= (1.838*1)+0
b= 1.838
The cutoff values that separates rejected thermometers from the others are -1.838 and 1.838 degrees C.
I hope it helps!
