
We know that, in ∆ABC,
∠A+∠B+∠C = 180°
But the triangle is right angled at C
ie., ∠C = 90°
Therefore, ∠A+∠B+ 90° = 180°
⇒ ∠A + ∠B = 90°
Therefore, <u>cos(A + B) = cos 90º = 0</u>
I think the answer is going to be 3s
Answer:
C. is your answer
Step-by-step explanation:
Answer: (A) and (A)
<u>Step-by-step explanation:</u>
