The location of the y value of R' after using the translation rule is -10
<h3>What will be the location of the y value of R' after using the translation rule? </h3>
The translation rule is given as:
(x + 4, y - 7)
The pre-image of R is located at (-17, -3)
Rewrite as
R = (-17, -3)
When the translation rule is applied, we have:
R' = (-17 + 4, -3 - 7)
Evaluate
R' = (-13, -10)
Remove the x coordinate
R'y = -10
Hence, the location of the y value of R' after using the translation rule is -10
Read more about translation at:
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Answer:
PEMDAS
Step-by-step explanation:
P=Parenthesis
E=Exponent
M=Multiply
D=Division
A=Addition
S=Subtract
When X=0, the function would be:
<span>f(x) = 4x^3 -20x2 + 24x
0= </span><span>4x^3 -20x2 + 24x ----->divide all by x
</span>x(4x^2 -20x + 24) =0 ------> split -20x into -12x and -8x
x(4x^2 -12x -8x + 24)
x{4x(x-3) - 8(x -3}
x(4x-8) (x-3)
x1= 0
x2= 8/4= 2
x3= 3
Answer:
Option 3 is the correct answer.
Step-by-step explanation:
In this graph the red area is above the line y = -1 which represents y ≥ (-1)
Another graph is of a line y = mx + c which passes through (2, -1) and (0, 0)
where m = (y-y')/(x-x') = (1+0)/(0-2) = -1/2
and y intercept c = 0
Therefore line is y = -1/2x
and the blue area will be y ≤ -1/2x below the line.
Hence Option 3 is the answer.
Answer:
2
Step-by-step explanation:
Arc length = r × theta
Arc length = 5 × 0.4
= 2
