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Tema [17]
3 years ago
7

HURRY I NEED HELP: Write an equation in point-slope form of the line that passes through the point (3, 5) and has a slope of m=−

1.
Mathematics
1 answer:
skelet666 [1.2K]3 years ago
6 0

Answer:

\huge y - 5 =  - 1(x - 3) \\

Step-by-step explanation:

To find an equation of a line in point slope form when given the slope and a point we use the formula

y -  y_1 = m(x -  x_1)

From the question we have the final answer as

y - 5 =  - 1(x - 3)

Hope this helps you

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HELP NEEDED PLEASE!!!
postnew [5]

Using vector concepts, it is found that:

The component form is of approximately (-9.58, 7,22). It means that the ship is about 9.58 miles to the west and about 7.22 miles to the north of where the ship left the port.

<h3>How can a vector be represented in component notation?</h3>

Given a magnitude M and angle \theta, then a vector V can be represented as follows in component notation:

V = (M\cos{\theta}, M\sin{\theta})

In this problem, the magnitude and the angle are given, respectively, by:

M = 12, \theta = 143^\circ

Hence:

V = [12cos(143º), 12sin(143º)] = (-9.58, 7,22).

Which means a displacement of 9.58 miles to the west(negative x = west) and 7.22 miles to the north(positive y = north).

The component form is of approximately (-9.58, 7,22). It means that the ship is about 9.58 miles to the west and about 7.22 miles to the north of where the ship left the port.

More can be learned about vectors at brainly.com/question/24606590

#SPJ1

8 0
2 years ago
What is the cosine of 45°
Degger [83]
Cosine 45° = √2/2 (Square root of 2 over 2)
4 0
3 years ago
PLEASE HELP ASAP which equation of a like has a slope of -2/3 and passes thought point (-3,-1)
coldgirl [10]

Answer:

Skill Tests

With a partner, complete the Skill Tests for the six areas of skill-related fitness and record both your scores and your partner’s scores below. Answer the reflection questions.

My Scores:

Agility – Agility Square Test:

Speed – Stay on Your Toes Test:

Reaction Time – Ready, Set, Go Test:

Balance – Stork Stance Test:

Coordination – Off the Wall Test:

Power – Standing Long Jump Test:

Partner Scores:

Agility – Agility Square Test:

Speed – Stay on Your Toes Test:

Reaction Time – Ready, Set, Go Test:

Balance – Stork Stance Test:

Coordination – Off the Wall Test:

Power – Standing Long Jump Test:

Compare your scores to your partner’s scores. Explain the reason for any differences.

How can improving your balance and coordination affect your performance in sports or recreational activities?

What activity was the most difficult for you to perform? Why?

Describe an activity that could help improve your striking and your reaction time skills.

Select a physical activity or sport that you have never done but would like to try one day. Identify at least one element of skill-related fitness that is important to being successful in this activity.

What power-increasing activities do you need to perform regularly to improve your performance?

8 0
3 years ago
Michael has 265 baseball cards. He wants to put them in packs of 9 cards each. How many cards will he have left over?
viktelen [127]
Michael will have 4 cards left because 265/9=29.4444444... then i do 29 (from the 29.4444) times 9 which gives me 261 and i did 265-261.
6 0
3 years ago
A major cab company in Chicago has computed its mean fare from O'Hare Airport to the Drake Hotel to be $28.75 , with a standard
bulgar [2K]

Answer:

Following are the solution to the given choices:

Step-by-step explanation:

Using chebyshev's theorem :

\to P(|(x-\mu)|\leq k \sigma)\geq 1- \frac{1}{k^2}\\\\here \\ \to \mu=28.75\\\\ \to \sigma=4.44

In point a)  

\to |(x-\mu)|= |20.17-28.75|=8.58 and \sigma=4.44 \\\\so, \\k= \frac{ |(x-\mu)| }{\sigma}

  = \frac{8.58}{4.44} \\\\ =1.9 \\\\ =2

value= (1- \frac{1}{k^2}) \times 100 \% =75\%

In point b)

\to (1- \frac{1}{k^2}) \times 100 \% =84\% \\\\\to (1- \frac{1}{k^2})=0.84 \\\\\to \frac{1}{k^2} =0.16 \\\\\to \frac{1}{k}=0.4\\\\ \to k=2.5 \\\\\to |(x-\mu)| \leq k \sigma  \\\\= |(x-\mu)|\leq 2.5 \times 4.44  \\\\  = |(x-\mu)|\leq 1.11 \\\\ =  (28.75\pm 11.1) \\\\\to \text{fares lies between}(17.65,39.85)

In point c)

\to 99.7 \% \\ lie \ between=28.75 \pm z(.03)\times \sigma \\\\ =28.75\pm 2.97 \times 4.44\\\\=(28.75\pm 13.1)\\\\=(15.65,41.85)\\

In point d)

using standard normal variate

x=20.17\\\\  z=-2 \\\\x=37.13\\\\ z=2\\\\\to P(20.17

8 0
3 years ago
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