Answer:
√(4/5)
Step-by-step explanation:
First, let's use reflection property to find tan θ.
tan(-θ) = 1/2
-tan θ = 1/2
tan θ = -1/2
Since tan θ < 0 and sec θ > 0, θ must be in the fourth quadrant.
Now let's look at the problem we need to solve:
sin(5π/2 + θ)
Use angle sum formula:
sin(5π/2) cos θ + sin θ cos(5π/2)
Sine and cosine have periods of 2π, so:
sin(π/2) cos θ + sin θ cos(π/2)
Evaluate:
(1) cos θ + sin θ (0)
cos θ
We need to write this in terms of tan θ. We can use Pythagorean identity:
1 + tan² θ = sec² θ
1 + tan² θ = (1 / cos θ)²
±√(1 + tan² θ) = 1 / cos θ
cos θ = ±1 / √(1 + tan² θ)
Plugging in:
cos θ = ±1 / √(1 + (-1/2)²)
cos θ = ±1 / √(1 + 1/4)
cos θ = ±1 / √(5/4)
cos θ = ±√(4/5)
Since θ is in the fourth quadrant, cos θ > 0. So:
cos θ = √(4/5)
Or, written in proper form:
cos θ = (2√5) / 5
The correct answer is 22.45
So I guess we are solving for x here :)
So here is my work...
a=2x+6xz
Basically I think it would be
a=6xz+2x
WAIT WAIT NO I'M WRONG FORGIVE ME!
It's x=a/2(1+3z)
Answer:
x = 2sqrt(5)
Step-by-step explanation:
We can use the Pythagorean theorem to solve
The legs are x and 8/2 =4
and the hypotenuse is 6
a^2 + b^2 = c^2
x^2 +4^2 = 6^2
x^2 +16 = 36
Subtract 16 from each side
x^2 +16-16=36-16
x^2 = 20
Take the square root of each side
sqrt(x^2) = sqrt(20)
x = sqrt(4*5)
x = sqrt(4) sqrt(5)
x = 2sqrt(5)
If the larger angle is x and the smaller angle is y, y=(1/2)x+30 since it's 30 more than 1/2 of it. In addition, x+y=180 since they are supplementary. Plugging y=(1/2)x+30 into that, we get x+x/2+30=180=1.5x+30. Subtracting 30 from both sides, we get 1.5x=150. Next, we can divide both sides by 1.5 to get x=100 and y=(1/2)*100+30=50+30=80
