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Murrr4er [49]
3 years ago
5

A ball has a diameter of 14 inches. Which choice is closest to its surface area? Use 3.14 to approximate pi.

Mathematics
1 answer:
artcher [175]3 years ago
8 0
So we know the formula to find the surface area of a sphere (ball) is:
4 x pi x r^2

to find the radius, divide the diameter by 2 to get:
14 / 2 = 7

now we substitute in the values:
4 x pi x 7^2

simplify:
4 x pi x 49

simplify:
12.56 x 49

simplify:
615.44 inches

the answer is above in bold
hope it helped :)
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Is -2/3 a rational number
Gelneren [198K]

Answer:

yes it is rational, as it can be expressed in the form p/q where p=-2 and q=3

Step-by-step explanation:

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3 years ago
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What is the value of the expression below? 3/8+(-4/5)+(-3/8)+5/4
Crazy boy [7]
It will help you!

=-17/40+-3/8+5/4

= -4/5+5/4

= 9/20 

And the answer is 9/20 or decimals (0.45)

4 0
3 years ago
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The answer with an explanation please
ValentinkaMS [17]

Answer:

5C

6C

7D

8B

Step-by-step explanation:

5) C because median is the middle of the set of numbers source A median is 4 source B median is 6 and 4 is 2 less than 6.

6) C  because there are  6 numbers altogether and 1 6s on a dice so 6+6 because we have two dice and 2 6s on both so 2/12 or simplified 1/6

7) D because mean is all the numbers add up divided by the amount of numbers so 20+25+30+20+30 = 125 and 125 ÷ 5 = 25

8 B because mean is all the numbers add up divided by the amount of numbers so

5+6+7+8+8+8+8+8+8+9+9 = 76 ÷ by 10 is 7.6

7+7+7+7+8+8+8+8+10+10 = 80 ÷ by 10 = 8

8 + 7.6 = 15.6 ÷ 2 = 7.8 and B is closest to 7.8

4 0
3 years ago
How many pounds of a 15% copper alloy must be mixed with 700lb of a 30% copper alloy to maybe a 25.5% copper alloy
lisov135 [29]

Answer:

300\; \rm lb.

Step-by-step explanation:

Let x represent the mass (in pounds) of that 15\% copper alloy required, such that the final mixture would contain 25.5\% copper by mass.

Consider: if x pounds of that 15\% copper alloy is mixed with 700 pounds that 30\% copper alloy, what would be the mass of copper in the mixture?

  • Mass of copper in x pounds of that 15\% copper alloy: (0.15\, x)\; \rm lb.
  • Mass of copper in 700 pounds of that 30\% copper alloy: 700 \times 0.30 = 210\; \rm lb.

Therefore, the mixture would contain (210 + 0.15\, x) \; \rm lb of copper.

The mass of that mixture would be (700 + x)\; \rm lb. The mass fraction of copper in that mixture would be:

\displaystyle \frac{(210 + 0.15\, x)\; \rm lb}{(700 + x)\; \rm lb} \times 100\%.

This ratio is supposed to be equal to 25.5\%. These two pieces of equations combine to give an equation about x:

\displaystyle \frac{(210 + 0.15\, x)\; \rm lb}{(700 + x)\; \rm lb} \times 100\% = 25.5\%.

\displaystyle \frac{210 + 0.15\, x}{700 + x} = 0.255.

Simplify and solve for x:

210 + 0.15\, x= 0.255\, (700 + x).

(0.255 - 0.15)\, x= 210 - 0.255 \times 700.

\displaystyle x = \frac{210 - 0.255 \times 700}{0.255 - 0.15} = 300.

Therefore, 300\; \rm lb of that 15\% alloy would be required.

4 0
3 years ago
Apply the distributive property to factor out the GCF.<br><br> 22c + 33d=________
slava [35]

Answer:

Step-by-step explanation:

3 0
3 years ago
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