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3 years ago

This is the process that cells reproduce and replace old or damaged cells.

Chemistry

1 answer:

Kipish [7]3 years ago

8 0

Answer:

Mitosis

Explanation:

This is the process that cells reproduce and replace old or damaged cells.

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How many grams of H2O will be formed when 32.0 g H2 is mixed with 84.0 g of O2 and allowed to react to form water

Zarrin [17]

Answer:

94.58 g of $H_2O$

Explanation:

For this question we have to start with the reaction:

$H_2~+~O_2~->~H_2O$

Now, we can balance the reaction:

$2H_2~+~O_2~->~2H_2O$

We have the amount of $H_2$ and the amount of $O_2$ . Therefore we have to find the limiting reactive, for this, we have to follow a few steps.

1) Find the moles of each reactive, using the molar mass of each compound ( $H_2~=~2~g/mol~~O_2=~32~g/mol$ ).

2) Divide by the coefficient of each compound in the balanced reaction ("2" for $H_2$ and "1" for $O_2$ ).

Find the moles of each reactive

$32.0~g~H_2\frac{1~mol~H_2}{2~g~of~H_2}=15.87~mol~H_2$

$84.0~g~of~O_2\frac{1~mol~of~O_2}{32~g~of~O_2}=2.62~mol~of~O_2$

Divide by the coefficient

$\frac{15.87~mol~H_2}{2}=7.94$

$\frac{2.62~mol~of~O_2}{1}=2.62$

The smallest values are for $H_2$ , so hydrogen is the limiting reagent. Now, we can do the calculation for the amount of water:

$32.0~g~H_2\frac{1~mol~H_2}{2~g~of~H_2}\frac{2~mol~H_2O}{2~mol~H_2}\frac{18~g~H_2O}{1~mol~H_2O}=94.58~g~H_2O$

We have to remember that the molar ratio between $H_2O$ and $H_2$ is 2:2 and the molar mass of $H_2O$ is 18 g/mol.

6 0

3 years ago

Which of the following circumstances will result in a reaction that is spontaneous at all temperatures?

sladkih [1.3K]

Negative enthalpy change and positive entropy change. I am sure that's the answer!

4 0

4 years ago

Read 2 more answers

Mécanisme de la bromation du butane

Darya [45]

Yes yes yes yes yes yes yes yes yes.

4 0

3 years ago

A certain flexible weather balloon contains 3.5 L of helium gas. Initially, the balloon is in WP at 8500ft, where the temperatur

Advocard [28]

Answer:

$\large \boxed{\text{3.9 L}}$

Explanation:

We can use the Combined Gas Laws to solve this problem

$\dfrac{p_{1}V_{1} }{T_{1}} = \dfrac{p_{2}V_{2}}{T_{2}}$

Data

p₁ = 571.2 Torr; p₂ = 400 Torr

V₁ = 3.5 L; V₂ = ?

T₁ = 21.5 °C; T₂ = 6.8 °C

Calculations

(a) Convert the temperatures to kelvins

T₁ = (21.55 + 273.15) K = 294.70 K

T₂ = (6.8 + 273.15) K = 279.95 K

(b) Calculate the new volume

$\begin{array}{rcl}\dfrac{p_{1}V_{1} }{T_{1}} & = & \dfrac{p_{2}V_{2}}{T_{2}}\\\\\dfrac{\text{571.2 Torr $\times$ 3.5 L}}{\text{294.65 K}} & = & \dfrac{\text{400 Torr} \times V_{2}}{\text{279.95 K}}\\\\\text{6.78 L} & = & \text{1.429V}_{2}\\\\V_{2} & = & \textbf{4.7 L}\\\end{array}\\\text{The new volume of the balloon is $\large \boxed{\textbf{4.7 L}}$}$

3 0

3 years ago

Read 2 more answers

What type of bond holds nitrogen and sulfur together in a compound?

Natasha_Volkova [10]

Answer:

b covalent . A covalent bond holds atoms that share valence electrons

6 0

3 years ago