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2 years ago

How does a conjugate acid differ from its conjugate base?

1 answer:

3 0

The conjugate acid is differ from its conjugate base as, conjugate acid is formed by strong base whereas conjugate base is formed by strong acid.

conjugate base is differ from conjugate acids by the presence of the proton. The conjugate acid is formed when proton is added to the bases whereas conjugate bases is formed when proton is released by the acids.

Example of corrugate acids are given below.

$NH_{3}$ → $NH_{2} ^{-} +H^{+}$

In the above example $NH_{2} ^{-}$ is conjugate acids.

Learn about conjugate acid

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Calculate ∆h0 for the reaction 2 n2(g) + 5 o2(g) −→ 2 n2o5(g) given the data h2(g) + 1 2 o2(g) −→ h2o(ℓ) ∆h 0 f = −283.7 kj/mol

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Based on Hess's Law:

2 N2(g) + 6 O2(g) + 2 H2(g) −→ 4 HNO3(l) ∆Hf = (−171.9 kJ/mol)(4 mol) 
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2 N2(g) + 5 O2(g) −→ 2 N2O5(g) ∆H0 = 32.8 kJ

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4 years ago

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3 years ago

Why would a high speed collision cause more damage than a low speed collision?

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3 years ago

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A 36.165 mg sample of a chemical known to contain only carbon, hydrogen, sulfur, and oxygen is put into a combustion analysis ap

anyanavicka [17]

Answer:

C6H12SO2

Explanation:

Step 1:

Data obtained from the question.

First experiment:

Mass of the compound = 36.165 mg

Mass of CO2 = 64.425 mg

Mass of H2O = 26.373 mg

Second experiment:

Mass of compound = 47.029 mg

Mass of SO2 = 20.32 mg

Step 2:

Determination of the mass of C, H and S. This is illustrated below:

Molar Mass of CO2 = 12 + (2x16) = 44g/mol

Mass of C in CO2 = 12/44 x 64.425 Mass of C = 17.57 mg

Molar Mass of H2O = (2x1) + 16 = 18g/mol

Mass of H in H2O = 2/18 x 26.373

Mass of H = 2.93 mg

Molar Mass of SO2 = 32 + (16x2) = 64g/mol

Mass of S in SO2 = 32/64 x 20.32

Mass of S = 10.16 mg

Step 3:

Determination of the the percentage composition of C, H, S and O. This is illustrated below:

% of C = 17.57/36.165 x 100 = 48.58%

% of H = 2.93/36.165 x 100 = 8.10%

% of S = 10.16/47.029 x 100 = 21.60%

% of O = 100 - (48.58 + 8.1 + 21.6)

% of O = 21.72%

Step 4:

Divide by their molar mass

C = 48.58x10^-3/12 = 4.0483

H = 8.10/1 = 8.1

S = 21.60/32 = 0.675

O = 21.72/16 = 1.3575

Step 5:

Divide by the smallest:

C = 4.0483/0.675 = 6

H = 8.1/0.675 = 12

S = 0.675/0.675 = 1

O = 1.3575/0.675 = 2

Therefore, the empirical formula is C6H12SO2

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3 years ago