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Flura [38]
3 years ago
6

Balancing

Chemistry
1 answer:
Kruka [31]3 years ago
5 0
2 in front of H2. Technically nothing in front of O2 otherwise put a 1 then a 2 in front of H2O

2H20 + 1O2 —— > 2H2O
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Cacl2+2AgNO3(aq)-> Ca(No3)2 (aq)+2AgCl (s) if 25.0mL of a 2.00 m CaCl2 solution is used for the reaction shown above how many
antiseptic1488 [7]

Answer:

n_{Cl^-}=0.1molCl^-

Explanation:

Hello,

In this case, given the 2.00 M solution, we can compute the moles of calcium chloride that reacted:

n_{CaCl_2}=2.00\frac{mol}{L} *25.0mL*\frac{1L}{1000mL}=0.05molCaCl_2

Then, since in one mole of calcium chloride, we find two moles of chloride ions (see subscript), we can compute the moles of chloride ions that were involved in the reaction as shown below:

n_{Cl^-}=0.05molCaCl_2*\frac{2molCl^-}{1molCaCl_2}\\ \\n_{Cl^-}=0.1molCl^-

Best regards.

4 0
3 years ago
Read 2 more answers
How to find pH value
yuradex [85]

Answer:

take the log of a given hydrogen ion concentration and reverse the sign.

Explanation:

6 0
3 years ago
Solid iron combines with oxygen gas to form solid iron(III) oxide. Which of the following equations best describes this reaction
Alexus [3.1K]

Answer:

B.  4 Fe + 3 0₂---> 2 Fe₂O3        

Explanation:

(A) Ir + O₂--> IrO₂                                 No:  Ir is iridium

(B) 4 Fe + 3 0₂---> 2 Fe₂O3                Yes:  Fe is iron and O is oxygen,                  and the equation is balanced.

(C) I+ 0₂ ---> 10₂                                  No:  I is iodine

(D) 3 Ir + 0₂ -> 6 Ir₂03                         No:  I is iodine

3 0
2 years ago
0.65 moles of O2 originally at 85°C is cooled
soldier1979 [14.2K]

Answer:

2.09 atm

Explanation:

We can solve this problem by using the equation of state for an ideal gas, which relates the pressure, the volume and the temperature of an ideal gas:

pV=nRT

where

p is the pressure of the gas

V is its volume

n is the number of moles

R is the gas constant

T is the absolute temperature

In this problem we have:

n = 0.65 mol is the number of moles of the gas

V = 8.0 L is the final volume of the gas

T=40C+273=313 K is the temperature of the gas

R=0.082 atm L mol^{-1} K^{-1} is the gas constant

Solving for p, we find the final pressure of the gas:

p=\frac{nRT}{V}=\frac{(0.65)(0.082)(313)}{8.0}=2.09 atm

8 0
4 years ago
The chemical combination of two or more different atoms in fixed amounts is called a(n)
Inga [223]
The answer is B I'm really positive
3 0
4 years ago
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