Answer:
Because we need to dispense 4.7 mL, the volume reading in the pipet is the 5.3 mL line.
Explanation:
First we use C₁V₁=C₂V₂ in order to <u>calculate the required volume of concentrated HCl</u> (V₁):
12.85 M * V₁ = 0.600 M * 100 mL
V₁ = 4.7 mL
<u>So we need to dispense 4.7 mL of the concentrated HCl solution</u>. The mark in the pipet that would contain that volume would be 10.0 - 4.7 = 5.3 mL
2NaOH+H2SO4--> Na2SO4+2H2O
80g NaOH(40g/mol)--> 36g H2O (18g/mol)
65.5 x (1/40g/mol)= 1.64 moles of NaOH
1.64 x 18g/mol= 29.5 g H2O
Answer:
See below
Explanation:
Reactions require successful collisions between elements or molecules. A rise in temperature increases the movement of molecules. The more movement, the more collisions. The more collisions, the more reactions. The collisions release energy as heat which warms the flask and so on.
Answer:
The new partial pressures after equilibrium is reestablished:



Explanation:

At equilibrium before adding chlorine gas:
Partial pressure of the 
Partial pressure of the 
Partial pressure of the 
The expression of an equilibrium constant is given by :


At equilibrium after adding chlorine gas:
Partial pressure of the 
Partial pressure of the 
Partial pressure of the 
Total pressure of the system = P = 263.0 Torr




At initail
(13.2) Torr (32.8) Torr (13.2) Torr
At equilbriumm
(13.2-x) Torr (32.8-x) Torr (217.0+x) Torr


Solving for x;
x = 6.402 Torr
The new partial pressures after equilibrium is reestablished:


