2 years ago

how many grams of water can be produced when 65.5 grams of sodium hydroxide react with excess sulfuric acid.

Chemistry

1 answer:

34kurt2 years ago

3 0

2NaOH+H2SO4--> Na2SO4+2H2O

80g NaOH(40g/mol)--> 36g H2O (18g/mol)

65.5 x (1/40g/mol)= 1.64 moles of NaOH

1.64 x 18g/mol= 29.5 g H2O

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